Theory of Machine Which of the following is a lower pair? Piston and cylinder Ball and socket i Both (A) and (B) above Cam and follower Piston and cylinder Ball and socket i Both (A) and (B) above Cam and follower ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A point B on a rigid link AB moves with respect to A with angular velocity ω rad/s. The total acceleration of B with respect to A will be equal to Vector sum of tangential component and Coriolis component Vector sum of radial component and tangential component Vector sum of radial component and Coriolis component Vector difference of radial component and tangential component Vector sum of tangential component and Coriolis component Vector sum of radial component and tangential component Vector sum of radial component and Coriolis component Vector difference of radial component and tangential component ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a four-bar chain it is required to give an oscillatory motion to the follower for a continuous rotation of the crank. For the lengths of 50 mm of crank and 70 mm of the follower, determine theoretical maximum length of coupler. The minimum length of the coupler will be Slightly more than 45 mm Slightly less than 45 mm 45 mm 95 mm Slightly more than 45 mm Slightly less than 45 mm 45 mm 95 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In S.H.M., the velocity vector w.r.t. displacement vector Leads by 180° Are in phase Lags by 90° Leads by 90° Leads by 180° Are in phase Lags by 90° Leads by 90° ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Which of the below are inversions of slider crank mechanism?1. Oscillating cylinder engine mechanism2. Toggle mechanism3. Radial cylinder engine mechanism4. Quick return mechanism 1, 2 and 3 1, 2 and 4 2, 3 and 4 1, 3 and 4 1, 2 and 3 1, 2 and 4 2, 3 and 4 1, 3 and 4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h n = 2(l - 1) - 2j - h ANSWER DOWNLOAD EXAMIANS APP