Hydraulics and Fluid Mechanics in ME When time of closure tc = L/v0 (where L is length of pipe and v0 is speed of pressure wave), the portion of pipe length subjected to maximum head is L/2 L L/3 L/4 L/2 L L/3 L/4 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A Pelton wheel develops 1750 kW under a head of 100 meters while running at 200 r.p.m. and discharging 2500 liters of water per second. The unit speed of the wheel is 80 r.p.m. 40 r.p.m. 10 r.p.m. 20 r.p.m. 80 r.p.m. 40 r.p.m. 10 r.p.m. 20 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Rotameter is a device used to measure rotation flow absolute pressure velocity of fluid rotation flow absolute pressure velocity of fluid ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The power absorbed (in watts) in overcoming the viscous resistance of a footstep bearing is μ π³ N² R⁴ /3600 t μ π³ N² R⁴ /1800 t μ π³ N² R² /1800 t μ π³ N² R² /3600 t μ π³ N² R⁴ /3600 t μ π³ N² R⁴ /1800 t μ π³ N² R² /1800 t μ π³ N² R² /3600 t ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H12 - Ha2] ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Bernoulli's equation Z - p/w - v²/2g = constant Z + p/w + v²/2g = constant Z + p/w - v²/2g = constant Z - p/w + v²/2g = constant Z - p/w - v²/2g = constant Z + p/w + v²/2g = constant Z + p/w - v²/2g = constant Z - p/w + v²/2g = constant ANSWER DOWNLOAD EXAMIANS APP
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