Hydraulics and Fluid Mechanics in ME Coefficient of contraction is the ratio of Actual velocity of jet at vena contracta to the theoretical velocity Loss of head in the orifice to the head of water available at the exit of the orifice Area of jet at vena-contracta to the area of orifice Loss of head in the orifice to the head of water available at the exit of the orifice Actual velocity of jet at vena contracta to the theoretical velocity Loss of head in the orifice to the head of water available at the exit of the orifice Area of jet at vena-contracta to the area of orifice Loss of head in the orifice to the head of water available at the exit of the orifice ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The maximum efficiency of jet propulsion of a ship with inlet orifices at right angles to the direction of motion of ship, is 0.6 0.8 0.4 0.5 0.6 0.8 0.4 0.5 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The intensity of pressure at any point, in a liquid, is __________ to the depth of liquid from the surface. Directly proportional None of these Inversely proportional Equal Directly proportional None of these Inversely proportional Equal ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The specific weight of water is 1000 kg/m3 At mean sea level At 4°C temperature All of the listed here At normal pressure of 760 mm At mean sea level At 4°C temperature All of the listed here At normal pressure of 760 mm ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME With the same cross-sectional area and immersed in same turbulent flow, the largest total drag will be on a cylinder a streamlined body a sphere a circular disc of plate held normal to flow a cylinder a streamlined body a sphere a circular disc of plate held normal to flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity) tanθ = 2 a/g tanθ = a/2g tanθ = a2/2g tanθ = a/g tanθ = 2 a/g tanθ = a/2g tanθ = a2/2g tanθ = a/g ANSWER DOWNLOAD EXAMIANS APP
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