Machine Design When a hole of diameter ‘d’ is punched in a metal of thickness 't', then the force required to punch a hole is equal to (where τu = Ultimate shear strength of the material of the plate) π/4 × d² × tτu π/4 × d².τu πd.t.τu t.τu π/4 × d² × tτu π/4 × d².τu πd.t.τu t.τu ANSWER DOWNLOAD EXAMIANS APP
Machine Design Which of the following statement is correct regarding power screws? The efficiency of a self locking screw can not be more than 50% The efficiency of Acme (trapezoidal) thread is less than that of a square thread If the friction angle is less than the helix angle of the screw, then the efficiency will be more than 50% Both (A) and (B) The efficiency of a self locking screw can not be more than 50% The efficiency of Acme (trapezoidal) thread is less than that of a square thread If the friction angle is less than the helix angle of the screw, then the efficiency will be more than 50% Both (A) and (B) ANSWER DOWNLOAD EXAMIANS APP
Machine Design A connecting rod is designed as a All of these Strut Long column Short column All of these Strut Long column Short column ANSWER DOWNLOAD EXAMIANS APP
Machine Design When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to (1/2) × [M + √(M² + T²)] M + √(M² + T²) (1/2) × √(M² + T²) √(M² + T²) (1/2) × [M + √(M² + T²)] M + √(M² + T²) (1/2) × √(M² + T²) √(M² + T²) ANSWER DOWNLOAD EXAMIANS APP
Machine Design The face of the tooth is the Surface of the top of the tooth Surface of the tooth below the pitch surface Surface of the tooth above the pitch surface Width of the tooth measured along the pitch circle Surface of the top of the tooth Surface of the tooth below the pitch surface Surface of the tooth above the pitch surface Width of the tooth measured along the pitch circle ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length) (π/4) d² × τ × n 1.875 × (π/4) d² × τ × n 3 × (π/4) d² × τ × n 2 × (π/4) d² × τ × n (π/4) d² × τ × n 1.875 × (π/4) d² × τ × n 3 × (π/4) d² × τ × n 2 × (π/4) d² × τ × n ANSWER DOWNLOAD EXAMIANS APP
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