Machine Design The endurance limit of a material with finished surface in comparison to rough surface is More More or less depending on quantum of load Less Same More More or less depending on quantum of load Less Same ANSWER DOWNLOAD EXAMIANS APP
Machine Design In oilness bearings Grease required to be applied after some intervals The oil film is maintained by supplying oil under pressure Do not require external supply of lubricant The oil film pressure is generated only by the rotation of the journal Grease required to be applied after some intervals The oil film is maintained by supplying oil under pressure Do not require external supply of lubricant The oil film pressure is generated only by the rotation of the journal ANSWER DOWNLOAD EXAMIANS APP
Machine Design The suitable material for belt in agricultural machinery is Balata gum Rubber Cotton duck Leather Balata gum Rubber Cotton duck Leather ANSWER DOWNLOAD EXAMIANS APP
Machine Design A screw is said to be over hauling screw, if the Friction angle is equal to helix angle Friction angle is more than helix angle Efficiency of screw is 100% Friction angle is less than helix angle Friction angle is equal to helix angle Friction angle is more than helix angle Efficiency of screw is 100% Friction angle is less than helix angle ANSWER DOWNLOAD EXAMIANS APP
Machine Design The fatigue stress concentration factor is defined as The ratio of endurance limit without stress concentration to the endurance limit with stress concentration The product of the endurance limits with and without stress concentration All of these The ratio of endurance limit with stress concentration to the endurance limit without stress concentration The ratio of endurance limit without stress concentration to the endurance limit with stress concentration The product of the endurance limits with and without stress concentration All of these The ratio of endurance limit with stress concentration to the endurance limit without stress concentration ANSWER DOWNLOAD EXAMIANS APP
Machine Design If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension) P1 + P2 [⅟₂ × (P1 + P2)] + Pc ⅟₂× (P1 + P2) [(√P1 + √P2)/2]² P1 + P2 [⅟₂ × (P1 + P2)] + Pc ⅟₂× (P1 + P2) [(√P1 + √P2)/2]² ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS