Machine Design The constant factor in case of R10 series of preferred numbers is 1.06 1.12 1.26 1.58 1.06 1.12 1.26 1.58 ANSWER DOWNLOAD EXAMIANS APP
Machine Design The maximum bending stress in a curved beam having symmetrical section always occur at the Neutral axis Inside fiber Outside fiber Centroidal axis Neutral axis Inside fiber Outside fiber Centroidal axis ANSWER DOWNLOAD EXAMIANS APP
Machine Design The pipe joint mostly used for pipes carrying water at low pressures is Union joint Socket joint Spigot and socket joint Nipple joint Union joint Socket joint Spigot and socket joint Nipple joint ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design If T₁ and T₂ are the tensions on the tight and slack sides of the belt respectively, and Tc is the centrifugal tension, then initial tension in the belt is equal to (T₁ + T₂ + Tc)/2 T₁ + T₂ + Tc (T₁ - T₂ + Tc)/2 T₁ - T₂ + Tc (T₁ + T₂ + Tc)/2 T₁ + T₂ + Tc (T₁ - T₂ + Tc)/2 T₁ - T₂ + Tc ANSWER DOWNLOAD EXAMIANS APP
Machine Design Taper on the cotter and slot is provided May be provided anywhere On both the sides On one side only On none of the sides May be provided anywhere On both the sides On one side only On none of the sides ANSWER DOWNLOAD EXAMIANS APP
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