Refrigeration and Air Conditioning Under cooling in a refrigeration cycle Increases C.O.P Decreases C.O.P Other factors decide C.O.P O.P remains unaltered Increases C.O.P Decreases C.O.P Other factors decide C.O.P O.P remains unaltered ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The bypass factor, in case of sensible cooling of air, is given by (where td₁ = Dry bulb temperature of air entering the cooling coil, td₂ = Dry bulb temperature of air leaving the cooling coil, and td₃ = Dry bulb temperature of the cooling coil) (td₂ -td₃)/( td₁ -td₃) (td₁ -td₃)/( td₂ -td₃) (td₃ -td₂)/( td₁ -td₃) (td₃ -td₁)/( td₂ -td₃) (td₂ -td₃)/( td₁ -td₃) (td₁ -td₃)/( td₂ -td₃) (td₃ -td₂)/( td₁ -td₃) (td₃ -td₁)/( td₂ -td₃) ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The coefficient of performance of Heat Pump is always ___ one. Equal to None of the listed here Less than Greater than Equal to None of the listed here Less than Greater than ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The vertical and uniformly spaced lines on a psychrometric chart indicates Specific humidity Wet bulb temperature Dry bulb temperature Dew point temperature Specific humidity Wet bulb temperature Dry bulb temperature Dew point temperature ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The optimum effective temperature for human comfort is Same in winter and summer Not dependent on season Higher in winter than in summer Lower in winter than in summer Same in winter and summer Not dependent on season Higher in winter than in summer Lower in winter than in summer ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning A heat pump working on a reversed Carnot cycle has a C.O.P. of 5. It works as a refrigerator taking 1 kW of work input. The refrigerating effect will be 4 kW 3 kW 2 kW 1 kW 4 kW 3 kW 2 kW 1 kW ANSWER DOWNLOAD EXAMIANS APP
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