Process Equipment and Plant Design Tube height in a calendria type evaporator is normally less than __________ metres. 3.5 2 5.5 1 3.5 2 5.5 1 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The thickness of segmental baffles (25 -35% cut truncated plates usually) is generally __________ the tube wall thickness. Equal to Half Twice Four times Equal to Half Twice Four times ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design With increase in pressure drop (for a given particle size), the dust collection efficiency of a cyclone separator will Remain unaffected Increase or decrease depending on the nature of the dust Decrease Increase Remain unaffected Increase or decrease depending on the nature of the dust Decrease Increase ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For a cylinderical internally pressurised vessel, which of the following closure types would withstand highest pressure, if each closure is of the same material and thickness? Flat plate Conical Ellipsoidal (2 : 1) Hemispherical Flat plate Conical Ellipsoidal (2 : 1) Hemispherical ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Pick out the wrong statement pertaining to the design of a basket type evaporator. There is no central downtake It is used for high viscosity liquor having large rate of scaling Downtake is formed by the annular space between the bundle and the shell The tube bundle is suspended on bracket There is no central downtake It is used for high viscosity liquor having large rate of scaling Downtake is formed by the annular space between the bundle and the shell The tube bundle is suspended on bracket ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Overall distillation column efficiency for most of the refinery columns can be given by (for μ = 0.07 - 1.4 cp and relative volatility < 4) (where η = overall column efficiency, % μ = molal average viscosity of feed at average column temperature and pressure, cp Δp = pressure drop per tray, psi) Η = 24.6 (Δp/μ) Η = 17 - 61.1 log μ Η = 0.25 log μ - 1.67 Η = 1.66 - 0.25 log μ Η = 24.6 (Δp/μ) Η = 17 - 61.1 log μ Η = 0.25 log μ - 1.67 Η = 1.66 - 0.25 log μ ANSWER DOWNLOAD EXAMIANS APP