Theory of Structures The yield moment of a cross section is defined as the moment that will just produce the yield stress in The outer most fibre of the section The inner most fibre of the section The fibre everywhere The neutral fibre of the section The outer most fibre of the section The inner most fibre of the section The fibre everywhere The neutral fibre of the section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel bar 20 mm in diameter simply-supported at its ends over a total span of 40 cm carries a load at its centre. If the maximum stress induced in the bar is limited to N/mm², the bending strain energy stored in the bar, is 611 N mm 711 N mm 511 N mm 411 N mm 611 N mm 711 N mm 511 N mm 411 N mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A short column (30 cm × 20 cm) carries a load P 1 at 4 cm on one side and another load P2at 8 cm on the other side along a principal section parallel to longer dimension. If the extreme intensity on either side is same, the ratio of P1 to P2 will be 2/3 8/5 3/2 5/8 2/3 8/5 3/2 5/8 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The greatest load which a spring can carry without getting permanently distorted, is called Proof load Proof resilience Stiffness Proof stress Proof load Proof resilience Stiffness Proof stress ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures There are two hinged semicircular arches A, B and C of radii 5 m, 7.5 m and 10 m respectively and each carries a concentrated load W at their crowns. The horizontal thrust at their supports will be in the ratio of None of these 2 : 1½ : 1 1 : 1½ : 2 1 : 1 : 2 None of these 2 : 1½ : 1 1 : 1½ : 2 1 : 1 : 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good All of these (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) E = 2N (1 + 1/m) All of these (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) E = 2N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP