Theory of Structures The forces in the members of simple trusses, may be analysed by Method of joints All of these Graphical method Method of sections Method of joints All of these Graphical method Method of sections ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures At yield point of a test piece, the material Regains its original shape on removal of the load Obeys Hooke’s law Behaves in an elastic manner Undergoes plastic deformation Regains its original shape on removal of the load Obeys Hooke’s law Behaves in an elastic manner Undergoes plastic deformation ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection due to a load W at the free end of a cantilever of length L and having flexural rigidity EI, is WL²/2EI WL3/3EI WL²/3EI WL3/2EI WL²/2EI WL3/3EI WL²/3EI WL3/2EI ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The steel will be (where Young’s modulus of steel is m times that of the timber). BD³ + mbd³)/6D] BD² + mbd²)/6D] BD² + mbd²)/4D] BD² + mbd³)/4D] BD³ + mbd³)/6D] BD² + mbd²)/6D] BD² + mbd²)/4D] BD² + mbd³)/4D] ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In the truss, the force in the member AC is t compressive t tensile 8.75 t tensile 6.25 t compressive t compressive t tensile 8.75 t tensile 6.25 t compressive ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If a three hinged parabolic arch, (span l, rise h) is carrying a uniformly distributed load w/unit length over the entire span, All of these S.F. will be zero throughout B.M. will be zero throughout Horizontal thrust is wl2/8h All of these S.F. will be zero throughout B.M. will be zero throughout Horizontal thrust is wl2/8h ANSWER DOWNLOAD EXAMIANS APP
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