Theory of Structures The forces in the members of simple trusses, may be analysed by All of these Method of sections Method of joints Graphical method All of these Method of sections Method of joints Graphical method ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A rolled steel joist is simply supported at its ends and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be, 15 M 13 M 14 M 16 m 15 M 13 M 14 M 16 m ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The load on a spring per unit deflection, is called Proof resilience Proof load Stiffness Proof stress Proof resilience Proof load Stiffness Proof stress ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The steel will be (where Young’s modulus of steel is m times that of the timber). BD² + mbd³)/4D] BD² + mbd²)/4D] BD³ + mbd³)/6D] BD² + mbd²)/6D] BD² + mbd³)/4D] BD² + mbd²)/4D] BD³ + mbd³)/6D] BD² + mbd²)/6D] ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Stress may be defined as Force per unit length Force per unit area None of these Force per unit volume Force per unit length Force per unit area None of these Force per unit volume ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) E = 2N (1 + 1/m) All of these (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) E = 2N (1 + 1/m) All of these ANSWER DOWNLOAD EXAMIANS APP
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