Theory of Structures The locus of the end point of the resultant of the normal and tangential components of the stress on an inclined plane, is Circle Straight line Ellipse Parabola Circle Straight line Ellipse Parabola ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures constant, depth of a cantilever of length of uniform strength loaded with Keeping breadth uniformly distributed load varies from zero at the free end and 3w l at the fixed end w l) at the fixed end 2w w l at the fixed end l) at the fixed end 3w l at the fixed end w l) at the fixed end 2w w l at the fixed end l) at the fixed end ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A truss containing j joints and m members, will be a simple truss if m = 3j – 2 j = 2m – 3 m = 2j – 3 j = 3m – 2 m = 3j – 2 j = 2m – 3 m = 2j – 3 j = 3m – 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A three hinged arch is generally hinged at its supports and Anywhere in the rib None of these At the crown At one quarter span Anywhere in the rib None of these At the crown At one quarter span ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A cantilever of length 2 cm and depth 10 cm tapers in plan from a width 24 cm to zero at its free end. If the modulus of elasticity of the material is 0.2 × 106 N/mm², the deflection of the free end, is 4 mm 5 mm 2 mm 3 mm 4 mm 5 mm 2 mm 3 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures parabolic arch of span and rise , is given by The equation of a y = h/l² × (1 – x ) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = 4h/l² × (1 – x) y = h/l² × (1 – x ) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = 4h/l² × (1 – x) ANSWER DOWNLOAD EXAMIANS APP
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