RCC Structures Design The weight of reinforced concrete, is generally taken as 2400 kg/m³ 2500 kg/m³ 2300 kg/m³ 2200 kg/m³ 2400 kg/m³ 2500 kg/m³ 2300 kg/m³ 2200 kg/m³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a wall on either side of a lintel opening is at least half of its effective span L, the load W carried by the lintel is equivalent to the weight of brickwork contained in an equilateral triangle, producing a maximum bending moment WL/6 WL/8 WL/4 WL/2 WL/6 WL/8 WL/4 WL/2 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Long and short spans of a two way slab are ly and lx and load on the slab acting on strips parallel to lx and ly be wx and wy respectively. According to Rankine Grashoff theory (wx/wy) = (ly/lx)² None of these (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)⁴ (wx/wy) = (ly/lx)² None of these (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)⁴ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of R.C.C. cantilever beams, is based on the resultant force at Mid span Mid span and fixed support Fixed end Free end Mid span Mid span and fixed support Fixed end Free end ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b + a)/8 M = pb (b - a)²/8 M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b + a)/8 M = pb (b - a)²/8 ANSWER DOWNLOAD EXAMIANS APP
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