RCC Structures Design The diameter of the column head support a flat slab, is generally kept 5.0 cm larger than the diameter of the column 4.0 cm larger than the diameter of the column 0.25 times the diameter of the column 0.25 times the span length 5.0 cm larger than the diameter of the column 4.0 cm larger than the diameter of the column 0.25 times the diameter of the column 0.25 times the span length ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A reinforced concrete cantilever beam is 3.6 m long, 25 cm wide and has its lever arm 40 cm. It carries a load of 1200 kg at its free end and vertical stirrups can carry 1800 kg. Assuming concrete to carry one-third of the diagonal tension and ignoring the weight of the beam, the number of shear stirrups required, is 35 45 40 30 35 45 40 30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The minimum thickness of a flat slab is taken L/32 for end panels without drops All listed here L/36 for interior panels without drop L/36 for end panels without drops L/32 for end panels without drops All listed here L/36 for interior panels without drop L/36 for end panels without drops ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Based on punching shear consideration, the overall depth of a combined footing under a column A, is (Area of the column A × Safe punching stress)/Load on column A (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) None of these (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) (Area of the column A × Safe punching stress)/Load on column A (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) None of these (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The maximum area of tension reinforcement in beams shall not exceed 1 6 0.15 % 4 % 1 6 0.15 % 4 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are tread and rise respectively of a stair, then R + 2T = 60 2R + T = 30 2R + T = 60 R + 2T= 30 R + 2T = 60 2R + T = 30 2R + T = 60 R + 2T= 30 ANSWER DOWNLOAD EXAMIANS APP