RCC Structures Design If T and R are tread and rise respectively of a stair, then 2R + T = 30 2R + T = 60 R + 2T = 60 R + 2T= 30 2R + T = 30 2R + T = 60 R + 2T = 60 R + 2T= 30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the width of the foundation for two equal columns is restricted, the shape of the footing generally adopted, is Trapezoidal Triangular Rectangular Square Trapezoidal Triangular Rectangular Square ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design With usual notations the depth of the neutral axis of a balanced section, is given by mc/t = (d - n)/n t/mc = (d + n)/n mc/t = n/(d - n) t/mc = (d - n)/n mc/t = (d - n)/n t/mc = (d + n)/n mc/t = n/(d - n) t/mc = (d - n)/n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond length is given by (π/4). (ft .d3/fb) (π/4). (ft .d/fb) ft .d/4fb π ft .d²/fb (π/4). (ft .d3/fb) (π/4). (ft .d/fb) ft .d/4fb π ft .d²/fb ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Top bars are extended to the projecting parts of the combined footing of two columns L distance apart for a distance of One-fourth the distance of projection 0.1 L from the outer edge of column 0.1 L from the centre edge of column Half the distance of projection One-fourth the distance of projection 0.1 L from the outer edge of column 0.1 L from the centre edge of column Half the distance of projection ANSWER DOWNLOAD EXAMIANS APP
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