RCC Structures Design If T and R are tread and rise respectively of a stair, then 2R + T = 30 R + 2T= 30 2R + T = 60 R + 2T = 60 2R + T = 30 R + 2T= 30 2R + T = 60 R + 2T = 60 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a simply supported slab, alternate bars are curtailed at 1/7th of the span 1/4th of the span 1/6th of the span 1/5th of the span 1/7th of the span 1/4th of the span 1/6th of the span 1/5th of the span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If jd is the lever arm and ΣO is the total perimeter of reinforcement of an R.C.C. beam, the bond stress at the section having Q shear force, is 2 × Q/jdƩO Q/3jdƩO Q/2jdƩO Q/jdƩO 2 × Q/jdƩO Q/3jdƩO Q/2jdƩO Q/jdƩO ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 1343, total shrinkage for a pre-tensioned beam, is 3.5 × 10⁻⁵ 3.0 × 10⁻² 3.0 × 10⁻³ 3.0 × 10⁻⁵ 3.5 × 10⁻⁵ 3.0 × 10⁻² 3.0 × 10⁻³ 3.0 × 10⁻⁵ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The width of the flange of a L-beam, should be less than Breadth of the rib + four times thickness of the slab Breadth of the rib + half clear distance between ribs One-sixth of the effective span Least of the above Breadth of the rib + four times thickness of the slab Breadth of the rib + half clear distance between ribs One-sixth of the effective span Least of the above ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design High strength concrete is used in pre-stressed member To provide high bond stresses To overcome high bearing stresses developed at the ends To overcome bursting stresses at the ends All listed here To provide high bond stresses To overcome high bearing stresses developed at the ends To overcome bursting stresses at the ends All listed here ANSWER DOWNLOAD EXAMIANS APP
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