RCC Structures Design The weight of a foundation is assumed as 10% of wall weight 12% of wall weight 5% of wall weight 7% of wall weight 10% of wall weight 12% of wall weight 5% of wall weight 7% of wall weight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the average bending stress is 6 kg/cm² for M 150 grade concrete, the length of embedment of a bar of diameter d according to I.S. 456 specifications, is 48 d 58 d 38 d 28 d 48 d 58 d 38 d 28 d ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a singly reinforced beam Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Plane sections transverse to the centre line of the beam before bending remain plane after bending Steel possesses initial stresses when embedded in concrete Compression is borne entirely by concrete Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Plane sections transverse to the centre line of the beam before bending remain plane after bending Steel possesses initial stresses when embedded in concrete Compression is borne entirely by concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The minimum head room over a stair must be 230 cm 205 cm 210 cm 200 cm 230 cm 205 cm 210 cm 200 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A short column 20 cm × 20 cm in section is reinforced with 4 bars whose area of cross section is 20 sq. cm. If permissible compressive stresses in concrete and steel are 40 kg/cm² and 300 kg/cm², the Safe load on the column, should not exceed None of these 412,000 kg 41,200 kg 4,120 kg None of these 412,000 kg 41,200 kg 4,120 kg ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
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