RCC Structures Design The weight of a foundation is assumed as 12% of wall weight 7% of wall weight 5% of wall weight 10% of wall weight 12% of wall weight 7% of wall weight 5% of wall weight 10% of wall weight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are the tread and rise of a stair which carries a load w per square metre on slope, the corresponding load per square metre of the horizontal area, is w √(R + T)/T w (R + T)/T w (R/T) w √(R² + T²)/T w √(R + T)/T w (R + T)/T w (R/T) w √(R² + T²)/T ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The diameter of transverse reinforcement of columns should be equal to one-fourth of the diameter of the main steel rods but not less than 6 mm 5 mm 7 mm 4 mm 6 mm 5 mm 7 mm 4 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Pick up the incorrect statement from the following. The intensity of horizontal shear stress at the elemental part of a beam section, is directly proportional to Moment of the beam section about its neutral axis Area of the section Distance of the C.G. of the area from its neutral axis Shear force Moment of the beam section about its neutral axis Area of the section Distance of the C.G. of the area from its neutral axis Shear force ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The minimum stress ‘f’ on the beam subjected to a maximum bending moment ‘M’ is f = (A/P) - (M/Z) f = (P/A) - (M/6Z) f = (P/A) - (M/Z) f = (P/'- (Z/M) f = (A/P) - (M/Z) f = (P/A) - (M/6Z) f = (P/A) - (M/Z) f = (P/'- (Z/M) ANSWER DOWNLOAD EXAMIANS APP
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