RCC Structures Design A raft foundation is provided if its area exceeds the plan area of the building by 10 % 50 % 20 % 40 % 10 % 50 % 20 % 40 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good mc/t = (d - n)/t mc/t = n/(d - n) (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = (d - n)/t mc/t = n/(d - n) (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If L is the effective span of a R.C.C. beam which is subjected to maximum shear qmax at the ends, the distance from either end over which stirrups for the shear, are provided, is (L/2) (1 - 5/qmax) (L/3) (1 - 5/qmax) (L/2) (1 - 2/qmax) (L/2) (1 - 3/qmax) (L/2) (1 - 5/qmax) (L/3) (1 - 5/qmax) (L/2) (1 - 2/qmax) (L/2) (1 - 3/qmax) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the average bending stress is 6 kg/cm² for M 150 grade concrete, the length of embedment of a bar of diameter d according to I.S. 456 specifications, is 48 d 38 d 58 d 28 d 48 d 38 d 58 d 28 d ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)³ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ ANSWER DOWNLOAD EXAMIANS APP
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