Engineering Mechanics The velocity ratio of a differential pulley block with D and d as the diameters of larger and smaller pulley, is 2D/(D - d) D/(D - d) 2D/(D + d) D/(D + d) 2D/(D - d) D/(D - d) 2D/(D + d) D/(D + d) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The forces which meet at one point, but their lines of action __________ on the same plane, are Known as non-coplanar concurrent forces. Either A or B None of these Lie Do not lie Either A or B None of these Lie Do not lie ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Which of the following statement is correct in connection with projectiles? A path, traced by a projectile in the space, is known as trajectory. The angle, with the horizontal, at which a projectile is projected, is known as angle of projection. The velocity, with which a projectile is projected, is known as the velocity of projection. All of these A path, traced by a projectile in the space, is known as trajectory. The angle, with the horizontal, at which a projectile is projected, is known as angle of projection. The velocity, with which a projectile is projected, is known as the velocity of projection. All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the body falls freely under gravity, then the gravitational acceleration is taken as +9.8 m/s2 -9.8 m/s2 -8.9 m/s2 +8.9 m/s2 +9.8 m/s2 -9.8 m/s2 -8.9 m/s2 +8.9 m/s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Whenever a force acts on a body and the body undergoes a displacement, then Work is said to be done None of these Body has kinetic energy of translation Power is being transmitted Work is said to be done None of these Body has kinetic energy of translation Power is being transmitted ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS