Hydraulics and Fluid Mechanics in ME The total energy line lies over the centre line of the pipe by an amount equal to Velocity head Pressure head Pressure head + velocity head Pressure head - velocity head Velocity head Pressure head Pressure head + velocity head Pressure head - velocity head ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The force exerted by a jet of water (in a direction normal to flow) impinging on a fixed plate inclined at an angle θ with the jet is (waV/2g) × sin θ (waV²/g) × sin θ (waV²/2g) × sin 2θ (waV/g) × sin θ (waV/2g) × sin θ (waV²/g) × sin θ (waV²/2g) × sin 2θ (waV/g) × sin θ ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Reciprocating pumps are no more to be seen in industrial applications (in comparison to centrifugal pumps) because of Lower discharge Necessity of air vessel High initial and maintenance cost Lower speed of operation Lower discharge Necessity of air vessel High initial and maintenance cost Lower speed of operation ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In a lock-gate, the reaction between two gates is (where P = Resultant pressure on the lock gate, and α = Inclination of the gate with the normal to the side of the lock) 2p/sin (α/2) p/sinα p/2sinα 2p/sinα 2p/sin (α/2) p/sinα p/2sinα 2p/sinα ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME For starting an axial flow pump, its delivery valve should be Depends on starting condition and flow desired Could be either open or closed Closed Open Depends on starting condition and flow desired Could be either open or closed Closed Open ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a wholly drowned orifice is given by (where H1 = Height of water (on the upstream side) above the top of the orifice, H2 = Height of water (on the downstream side) above the bottom of the orifice, and H = Difference between two water levels on either side of the orifice) Q = Cd × bH2 × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH₁ × √(2gh) Q = Cd × bH × √(2gh) Q = Cd × bH2 × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH₁ × √(2gh) Q = Cd × bH × √(2gh) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS