Engineering Mechanics The time of flight (t) of a projectile on a horizontal plane is given by t = 2u. cosα/g t = 2u. sinα/g t = 2u. tanα/g t = 2u/g.sinα t = 2u. cosα/g t = 2u. sinα/g t = 2u. tanα/g t = 2u/g.sinα ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In a screw jack, the effort required to lower the load is __________ the effort required to raise the same load. None of these Less than More than Equal to None of these Less than More than Equal to ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P/m.a = 0 P × m.a = 0 P + m.a = 0 P - m.a = 0 P/m.a = 0 P × m.a = 0 P + m.a = 0 P - m.a = 0 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The point, through which the whole weight of the body acts, irrespective of its position, is known as Center of gravity Center of mass Center of percussion Moment of inertia Center of gravity Center of mass Center of percussion Moment of inertia ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a square of side a about its diagonal is a²/8 a⁴/16 a³/12 a⁴/12 a²/8 a⁴/16 a³/12 a⁴/12 ANSWER DOWNLOAD EXAMIANS APP
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