Engineering Mechanics The resultant of two equal forces ‘P’ making an angle ‘θ’, is given by 2P cotθ/2 2P sinθ/2 2P cosθ/2 2P tanθ/2 2P cotθ/2 2P sinθ/2 2P cosθ/2 2P tanθ/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When two elastic bodies collide with each other, The two bodies begin to regain their original shape The two bodies will momentarily come to rest after collision All of these The two bodies tend to compress and deform at the surface of contact The two bodies begin to regain their original shape The two bodies will momentarily come to rest after collision All of these The two bodies tend to compress and deform at the surface of contact ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Mass moment of inertia of a uniform thin rod of mass M and length (l) about its mid-point and perpendicular to its length is (2/3) Ml² (1/3) Ml² (3/4) Ml² (1/12) Ml² (2/3) Ml² (1/3) Ml² (3/4) Ml² (1/12) Ml² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When a body of mass 'm' attains a velocity 'v' from rest in time 't', then the kinetic energy of translation is 0.5 mgv2 mv2 mgv2 0.5 mv2 0.5 mgv2 mv2 mgv2 0.5 mv2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The time of flight (t) of a projectile on an upward inclined plane is(where u = Velocity of projection, α = Angle of projection, and β = Inclination of the plane with the horizontal.) t = g cos β/2u sin (α - β) t = 2u sin (α - β)/g cos β t = g cos β/2u sin (α + β) t = 2u sin (α + β)/g cos β t = g cos β/2u sin (α - β) t = 2u sin (α - β)/g cos β t = g cos β/2u sin (α + β) t = 2u sin (α + β)/g cos β ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P - m.a = 0 P + m.a = 0 P × m.a = 0 P/m.a = 0 P - m.a = 0 P + m.a = 0 P × m.a = 0 P/m.a = 0 ANSWER DOWNLOAD EXAMIANS APP
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