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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
The Thevenin’s resistance as seen through the terminals A and B is:

5 Ω
6 Ω
8 Ω
4 Ω

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SSC JE Electrical 2019 with solution SET-1
 Two inductors of 4H and 6H are connected in series. The equivalent inductance of this combination is

2.4 H
4 H
6 H
10 H

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Total inductance when inductor are connected in series
L = L1 + L2
L = 4 + 6 =10H
 

SSC JE Electrical 2019 with solution SET-1
 An electric heater is connected across 230V and it draws a current of 2A. Then the resistance offered by the heater is?

115 ohm
290 ohm
11.5 ohm
29 ohm

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Given
Voltage V = 230 V
Current I = 2 A
Resistance R = V/I
R = 230/2 = 115 Ω
 

SSC JE Electrical 2019 with solution SET-1
 4F2D is a/an number

Binary
Octal
Hexadecimal
Decimal

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The hexadecimal number system is also called base-16, a numeration system in which all numbers are represented using the symbols 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, and F only. The system is base of 16. The hexadecimal numbers are used to represent binary numbers because of ease of conversion and compactness.

SSC JE Electrical 2019 with solution SET-1
Please check out below figure.

10 Ω
2 Ω
1 Ω
5 Ω

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

From the figure it can be concluded that the voltmeter reads 5 volts as shown in the figure below. Based on the voltmeter and ammeter readings in the measuring network, determine the value of the resistor R Here Current I = 1/2 A = 0.5 A Voltage V = 5 V R = V/I = 0.5/5 R = 10Ω


SSC JE Electrical 2019 with solution SET-1
 In the circuit shown, if R = 0, then the phase angle between v(t) and i(t) is

60°
90°
30°
0°

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In the given circuit if R = 0 then the circuit becomes purely inductive. So the phase angle between v(t) and i(t) is 90°.


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