SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

Φ × A
dΦ ⁄ dA
dA ⁄ dΦ
dΦ − dA

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SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

2A
12A
4A
120A

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SSC JE Electrical 2019 with solution SET-1
 If admittance Y= a + jb, then a =?

Susceptance
Conductance
Reactance
Resistance

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