• HOME
  • QUIZ
  • CONTACT US
EXAMIANS
  • COMPUTER
  • CURRENT AFFAIRS
  • ENGINEERING
    • Chemical Engineering
    • Civil Engineering
    • Computer Engineering
    • Electrical Engineering
    • Mechanical Engineering
  • ENGLISH GRAMMAR
  • GK
  • GUJARATI MCQ

SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 When the only current source is active in the circuit, find the current through the 10Ω resistor

1.66 A
0.66 A
0 A
1.33 A

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
______ Opposes the change in circuit voltage

Capacitance
Resistance
Inductance
Inductive reactance

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 An alternator has 9 slots/pole. What is the value of the pitch factor if each coil spans 8 slot pitches

Cos 10°
Cos 60°
Cos 45°
Cos 30°

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Coil Span = 8
Pole Pitch = 9 slots/pole
Slot angle (α) = 180° / Pole Pitch = 180°/9 = 20°
Pitch Factor = cos(α/2) = cos (20/2)
Pitch Factor = cos 10°
 

SSC JE Electrical 2019 with solution SET-1
 The trade name of the Nickel-Copper alloy, that is used as a heating element is:

Nichrome
Eureka
Steel
Kanthal

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Constantin‘, also known as ‘Eureka wire‘, is the trade-name for a copper-nickel alloy (approx. 60:40 ratio) formulated in the late 1800s by Edward Weston.
 

SSC JE Electrical 2019 with solution SET-1
 The voltmeter is shown in the circuit reads:

24 V
2.4 V
12 V
1.2 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Total resistance in the given circuit
R = (250 + 250)MΩ = 500 MΩ
Current I = V/R = 24/(500 × 103)
Now the Voltage in the voltmeter
= \dfrac{{24}}{{500 \times {{10}^3}}} \times 250 \times {10^3}
V = 12 V
 

SSC JE Electrical 2019 with solution SET-1
In the circuit shown, find the equivalent resistance between A and B.

150 ohm
75 ohm
100 ohm
50 ohm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The resistance R3 &  R4 are connected in series
= (30 + 70) = 100Ω
Now three resistor i.e 100Ω, 100Ω & 50Ω is connected in parallel
1/Rp = 1/100 + 1/100 + 1/50
Rp = 100/4 = 25 Ω
Resistance 50Ω and 25Ω are connected in series.
Rtotal = (50 + 25)Ω
Rtotal = 75Ω
 


MORE MCQ ON SSC JE Electrical 2019 with solution SET-1

DOWNLOAD APP

  • APPLE
    from app store
  • ANDROID
    from play store

SEARCH

LOGIN HERE


  • GOOGLE

FIND US

  • 1.70K
    FOLLOW US
  • EXAMIANSSTUDY FOR YOUR DREAMS.
  • SUPPORT :SUPPORT EMAIL ACCOUNT : examians@yahoo.com

OTHER WEBSITES

  • GUJARATI MCQ
  • ACCOUNTIANS

QUICK LINKS

  • HOME
  • QUIZ
  • PRIVACY POLICY
  • DISCLAIMER
  • TERMS & CONDITIONS
  • CONTACT US
↑