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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 When the only current source is active in the circuit, find the current through the 10Ω resistor

1.33 A
1.66 A
0.66 A
0 A

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SSC JE Electrical 2019 with solution SET-1
 Which of the following fuel has the least calorific value?

LPG
Wood
Kerosene oil
Hydrogen

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In the above option, the wood has the lowest calorific value. Its value is around 17000 – 20000 kilojoule/kg.
The calorific value of LPG is 55000 kilojoule/kg.
The calorific value of Kerosene oil is 45000 kilojoule/kg.
The calorific value of hydrogen oil is 150000 kilojoule/kg.
 

SSC JE Electrical 2019 with solution SET-1
If N = linkage flux, then the linkage flux per unit current is defined as:

Magnetomotive force
Inductance
Leakage coefficient
Inductive reactance

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The inductance L of this coil is defined as the flux linkage per unit current and its unit is Henry.
L =Λ/I
Where
Λ = Flux linkage
I = current

SSC JE Electrical 2019 with solution SET-1
 The cheap and temporary system of the internal wiring is?

Conduit wiring
Cleat wiring
CTS or TRS wiring
Casing-capping

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SSC JE Electrical 2019 with solution SET-1
 Which of the following lamps employs a bimetallic strip?

Mercury vapor lamp
Incandescent lamp
Sodium vapor lamp
Fluorescent lamp

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SSC JE Electrical 2019 with solution SET-1
 A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is

0.4 V
−4 V
−2.5 V
−10 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given
Inductance L = 2 H
Rate of change of current di/dt = 5 A/sec
Self induced EMF = − (Rate of change of current × Inductance) = −L(di/dt)
= −(5 × 2) = −10V
 

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