Theory of Machine The secondary unbalanced force is maximum __________ in one revolution of the crank. Eight times Two times Sixteen times Four times Eight times Two times Sixteen times Four times ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r (sin 2θ/n) m.ω².r sinθ m.ω².r cosθ m.ω².r (cos 2θ/n) m.ω².r (sin 2θ/n) m.ω².r sinθ m.ω².r cosθ m.ω².r (cos 2θ/n) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a flat pivot bearing, considering uniform wear, is (where μ = Coefficient of friction, W = Load over the bearing, and R = Radius of bearing surface) (1/2) μ W R μ W R (3/4) μ W R (2/3) μ W R (1/2) μ W R μ W R (3/4) μ W R (2/3) μ W R ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted by a disc or plate clutch is same as that of Flat collar bearing Flat pivot bearing Conical pivot bearing Truncated conical pivot bearing Flat collar bearing Flat pivot bearing Conical pivot bearing Truncated conical pivot bearing ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A circular bar moving in a round hole is an example of Successfully constrained motion Partially constrained motion Completely constrained motion Incompletely constrained motion Successfully constrained motion Partially constrained motion Completely constrained motion Incompletely constrained motion ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS