Area Problems The ratio of the radii of two circle is 1:3 the radio of their areas is? None of these 1:3 1:9 1:6 None of these 1:3 1:9 1:6 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Radio of areas = area of first circle : area of 2nd circle= ?r2 / ?(3r)2= ?r2/ 9 ?r2= 1/9 = 1: 9
Area Problems The ratio of the area of the circumcircle and the incircle of a square is 1 : ?2 2 : 1 ?2 : 1 1 : 2 1 : ?2 2 : 1 ?2 : 1 1 : 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas of the circumcircle and incircle of a square = [(Diagonal)2?] / [(Side)2?]= [(Side x ?2)2] / (Side)2 = 2/1 or 2 : 1
Area Problems The wheel of an engine turns 350 times round its axle to cover a distance of 1.76 km. The diameter of the wheel is ?3 cm 3 cm 9 cm 3?3 cm ?3 cm 3 cm 9 cm 3?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Distance covered in 1 round = (Total Distance) / (Total round)= (1.76 x 1000)/350= 176/35 m ? 2?r = (1.76 x 100) / 35 cm2? = Diameter = 17600 x 7/22 x 35 = 160 cm
Area Problems A wheel makes 1000 revolutions in covering a distance of 88 km. the diameter of the wheel is? 40 meters 24 meters 28 meters 14 meters 40 meters 24 meters 28 meters 14 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Distance covered in one revolution = total distance travelled / total number of revolution. = ( 88 x 1000) / 1000 m = 88 mWe know that the distance covered in one revolution = circumference of the wheel.? ?d = 88? 22d / 7 = 88? d = 28 m
Area Problems The length of a rectangular field is 100 m and its breadth is 40 m. What will be the area of the field? (4 x 102) sq m (4 x 104) sq m (4 x 103) sq m (4 x 10) sq m (4 x 102) sq m (4 x 104) sq m (4 x 103) sq m (4 x 10) sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 100 x 40 = 4000 sq m= 4 x 103 sq m
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? None of these 4 meters 15 meters 3 meters None of these 4 meters 15 meters 3 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
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