Area Problems The ratio of the radii of two circle is 1:3 the radio of their areas is? 1:3 1:6 1:9 None of these 1:3 1:6 1:9 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Radio of areas = area of first circle : area of 2nd circle= ?r2 / ?(3r)2= ?r2/ 9 ?r2= 1/9 = 1: 9
Area Problems The Area of a square is 50 sq. units. Then the area of the circle drawn on its diagonal is? 50? sq. units 100? sq. units None of theas 25? sq. units 50? sq. units 100? sq. units None of theas 25? sq. units ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = (Diagonal)2 / 2 = 50? Diagonal = 10 units ? Radius of required circle = 5 unitsIts area = [? x (5)2 ] cm2= 25? units2
Area Problems The diagonals of two squares are in the ratio of 3 : 2. Find the ratio of their areas. 9 : 5 9 : 7 9 : 4 9 : 2 9 : 5 9 : 7 9 : 4 9 : 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the diagonals of the squares be 3x and 2x.? Ratio of their areas = [(1/2) (3x2)] / [(1/2) (2x2)] = 9/4
Area Problems The dimensions of a room are 10m x 7m x 5m. There are 2 doors and 3 windows in the room. The dimensions of the doors are 1m x 3m. One window is of size 2m x 1.5m and the other 2 windows are of size 1m x 1.5m. The cost of painting the walls at Rs. 3 per sq m is Rs.174 Rs.374 Rs.474 Rs.274 Rs.174 Rs.374 Rs.474 Rs.274 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of 4 walls = 2(l+b)h=2(10+7) x 5 = 170 sq mArea of 2 doors and 3 windows = 2(1x3)+(2x1.5)+2(1x1.5) = 12 sq marea to be planted = 170 -12 = 158 sq m Cost of painting = Rs. 158 x 3 = Rs. 474
Area Problems A hall 20 m long and 15 m broad is surrounded by a verandah of uniform width of 2.5 m. the cost of flooring the verandah at the rate of 3.50 per sq. meter is? Rs. 800 Rs. 600 Rs. 700 Rs. 500 Rs. 800 Rs. 600 Rs. 700 Rs. 500 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of verandah = [(25 x 20) -(20 x 15)] m2= 200 m2? Cost of flooring = Rs. (200 x 3.50)= Rs. 700
Area Problems A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is? 5.25 meters 10.5 meters 21 meters 7 meters 5.25 meters 10.5 meters 21 meters 7 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let outer radius be R and inner radius be r.Then from question 2?R - 2?r = 66? 2? (R-r) = 66? (2 x 22)/7 x (R - r) = 66? (R-r) = (66 x 7) / 44= 10.5 m
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