Area Problems The ratios of areas of two squares, one having its diagonal double than the other is 3:1 2:3 4:1 2:1 3:1 2:3 4:1 2:1 ANSWER DOWNLOAD EXAMIANS APP
Area Problems The base of right-angled triangle is 5 meters and hypotenuse is 13 meters . Its area will be? 25m2 30m2 28 m2 None of these 25m2 30m2 28 m2 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Altitude = ?(13)2 - (5)2= ?144 = 12m ? Area of the triangle = (5 x 12 ) / 2 m2= 30m2
Area Problems One side of a parallelogram is 14 cm. Its distance from the opposite side is 16 cm. The area of the parallelogram is? 210 sq. cm 112 sq. cm 56? sq. cm 224 sq. cm 210 sq. cm 112 sq. cm 56? sq. cm 224 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of parallelogram = Side of parallelogram x distance from the opposite side= 14 x 16 cm2= 224 cm2
Area Problems The difference between the circumference and the radius of a circle is 37 cm. The area of a circle is? 148 sq. cm 154 sq. cm 111 sq. cm 259 sq. cm 148 sq. cm 154 sq. cm 111 sq. cm 259 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 2?r - r = 37? [(2 x 22/7) -1]r= 37? 37r / 7= 37? r = 7 So, area of the circle =(22/7) x 7 x 7 cm2= 154 cm2
Area Problems The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is? 280 m 260 m none of these 360 m 280 m 260 m none of these 360 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m
Area Problems The length of a rectangular field is 100 m and its breadth is 40 m. What will be the area of the field? (4 x 104) sq m (4 x 102) sq m (4 x 10) sq m (4 x 103) sq m (4 x 104) sq m (4 x 102) sq m (4 x 10) sq m (4 x 103) sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 100 x 40 = 4000 sq m= 4 x 103 sq m
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