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Area Problems

Area Problems
The ratios of areas of two squares, one having its diagonal double than the other is

2:1
2:3
4:1
3:1

ANSWER DOWNLOAD EXAMIANS APP

Area Problems
The sides of a triangle area in the ratio of 1/3 : 1/4 : 1/5 and its perimeter is 94 cm. Find the length of the smallest side of the triangle .

24 cm
22.5 cm
18 cm
27 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given ratio = 1/3 : 1/4 : 1/5 = 20 : 15 : 12Let length of the sides be 20k, 15k and 12k.Then, according to the question,20k + 15k + 12k = 94? 47k = 94? k = 94/47 = 2Smallest side = 12k = 12 x 2 = 24 cm

Area Problems
The area of circle is 38.5 sq. cm. Its circumference is?

22 cm
121 cm
6.20 cm
11 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? ( 22 x r2) / 7 = 38.5? r2 =(38.5 x 7) /22? r = 3.5 cm? Circumference = 2 x (22/7) x 3.5 cm= 22 cm

Area Problems
If the side of a square is increased by 25%, then how much percent does its area get increased?

125
156.25
56.25
50

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let area 100 m2Then, side = 10 m New side = 125 % of 10= (125/100) x 10= 12.5 m New area = 12.5 x 12.5 m2=(12.5)2 sq. m? Increase in area = (12.5)2 - (10)2 m2= 22.5 x 2.5 m2=56.25 m2% Increase = 56.25 %

Area Problems
The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is?

360 m
280 m
none of these
260 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m

Area Problems
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

24
20
30
33

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the side of the square(ABCD) be x metres. Then, AB + BC = 2x metres. AC = √2x = (1.41x) m. Saving on 2x metres = (0.59x) m. Saving % = ❨ 0.59x x 100 ❩% = 30%

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