Area Problems The ratios of areas of two squares, one having its diagonal double than the other is 2:3 4:1 3:1 2:1 2:3 4:1 3:1 2:1 ANSWER DOWNLOAD EXAMIANS APP
Area Problems If the diagonal of a square is double, how does the area of the square change? Becomes two fold None of these Becomes three fold Becomes four fold Becomes two fold None of these Becomes three fold Becomes four fold ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas = area of original square / area of new square = [ d2 / 2 ] / [ (2d)2 / 2 ] = 1/4? New area becomes 4 fold.
Area Problems If the base of a rectangular is increased by 10% and the area is unchanged , then the corresponding altitude must to be decreased by? 10% 111/9 % 91/11 % 11% 10% 111/9 % 91/11 % 11% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let base = b and altitude = h Then, Area = b x h But New base = 110b / 100 = 11b / 10Let New altitude = HThen, Decrese = (h - 10h /11 )= h / 11? Required decrease per cent = (h/11) x (1 / h ) x 100 %= 91/11 %
Area Problems Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm? 154 sq.com 186 sq.com 164 sq.com 121 sq.com 154 sq.com 186 sq.com 164 sq.com 121 sq.com ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides) = 1/2 x (12 + 10) x 14 = 22 x 14/2 = 22 x 7 = 154 sq. cm
Area Problems In a rhombus, whose area is 144 sq.cmone of its diagonal is twice as long as the other, The lengths of its diagonals are? 12 cm, 24 cm 24 cm, 48 cm 6 ?2 cm, 12?2 cm 6 cm, 12 cm 12 cm, 24 cm 24 cm, 48 cm 6 ?2 cm, 12?2 cm 6 cm, 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of rhombus = (d1 x d2) / 2? (d x 2d ) / 2 = 144? d2 = 144? d = 12 ? Length of diagonal = 12 cm, 24 cm
Area Problems The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres? Data inadequate 40 120 None of these Data inadequate 40 120 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m
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