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Area Problems

Area Problems
The ratios of areas of two squares, one having its diagonal double than the other is

3:1
4:1
2:3
2:1

ANSWER DOWNLOAD EXAMIANS APP

Area Problems
What is the area of a square having perimeter 68 cm?

361 sq cm
284 sq cm
269 sq cm
289 sq cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,4a = 68 [ where a = side]?a = 68/4 = 17 cm? Required area = a2= (17)2 = 289 sq cm

Area Problems
The diagonal of a rectangle is √41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

41 cm
18 cm
20 cm
9 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

√l2 + b2 = √41. Also, lb = 20. (l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81 ⟹ (l + b) = 9. ∴ Perimeter = 2(l + b) = 18 cm

Area Problems
If 88 m wire is required to fence a circular plot of land, then the area of the plot is?

None of these
616 m2
526 m2
556 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference of circular plot= 88 m? 2 x (22/7) x r = 88? r = 88 x (7/22) x (1/2) = 14 m Now area = ?r2=( 22/7) x 14 x 14 m2= 616 m2

Area Problems
The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is?

32.72 km/hr.
29.46 km/hr.
31.68 km/hr.
36.25 km/hr.

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference = 2?r = 2 x (22 / 7) x 70 cm = 440 cm Distance travelled in 10 revolutions = 440 x 10 cm = 4400 cm = 44 m? Speed = distance / time= 44 / 5 m/sec= (44 / 5) x (18 / 5) km/hr = 31.68 km/hr

Area Problems
In ? ABC ,sides BC = 10 cm and height AD = 4.4 cm. If AC = 11 cm. Then altitude BE equals?

5 cm
5.6 cm
5.5 cm
4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We know that area of triangle = ( base x height ) / 2So area of triangle = (BC x AD) / 2 = (AC x BE) / 2 ? (10 x 4.4) / 2 = (11 x h) / 2? h= (10 x 4.4)/11 = 4 cm

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