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Area Problems

Area Problems
The ratios of areas of two squares, one having its diagonal double than the other is

2:3
3:1
2:1
4:1

ANSWER DOWNLOAD EXAMIANS APP

Area Problems
The circumference of a circle is 25 cm. Find the side of the square incribed in the circle.

21/??3 cm
29/??3 cm
25/??2 cm
23/??2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference of the circle = 2?r = 25? r = 25 / (2?)According to the formula,Side of inscribed square = r?2 = 25 / (2?r x ?2) = 25 / (??2 ) cm

Area Problems
The length and breadth of a square are increased by 40% and 30% respectively. The area of a resulting rectangle exceeds the area of the square by?

82%
None of these
42%
62%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the side of the square = 100 m So area of square = 100 x 100 = 10000.New length = 140 m, New breadth = 130 mIncrease in area = [(140 x 130) - (100 x 100)] m2= 8200 m2? Required increase percent = (8200/ 10000) x 100 % = 82%

Area Problems
If the side of a square is increased by 25%, then how much percent does its area get increased?

156.25
125
56.25
50

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let area 100 m2Then, side = 10 m New side = 125 % of 10= (125/100) x 10= 12.5 m New area = 12.5 x 12.5 m2=(12.5)2 sq. m? Increase in area = (12.5)2 - (10)2 m2= 22.5 x 2.5 m2=56.25 m2% Increase = 56.25 %

Area Problems
A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

rs.158
rs.258
rs.358
rs.58

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x  (75/100) = Rs. 258

Area Problems
A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece?

28 cm
14 cm
3.5 cm
7 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circular piece is 4 x 11 = 44 cm long, Then Circumference of circle is given by, 44 = pi x D, where D is the diameter D = 44 / pi Take pi = 22 / 7, then D = 44 / (22/7) = (44 x 7) / 22 D = 14 cm.

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