Area Problems Area of a square is 1/2 hectare. The diagonal of the square is? 50 meter 100 meter 50? 2 meter 250 meter 50 meter 100 meter 50? 2 meter 250 meter ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1/2 hectare = 10000 / 2 m2= 5000 m2Again Area = 1/2 x (Diagonal)2So 1/2 x (Diagonal)2 = 5000m2? Diagonal2= 10000 ? Diagonal = 100
Area Problems Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 154 sq m. 8 m 12 m 7 m 13 m 8 m 12 m 7 m 13 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of to the rope = Radius of circle According to the question,?r2 = 154 ? r2 = 154 x (7/22) = 7 x 7 = 49 ? r = ?49 = 7 m
Area Problems In a triangle ABC, BC = 5 cm AC = 12 cm and AB = 13 cm. The length of a altitude drawn from B on AC is? 4 cm 6 cm 7 cm 5 cm 4 cm 6 cm 7 cm 5 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? s= (13 + 5 + 12) / 2 cm = 15cms-a = 2 cm, s-b = 10 cm and s-c = 3 cm ? Area = ? (15 x 2 x 10 x 3 ) cm2= 30 cm2? (12 x h) / 2 = 30 ? h = 5 cm
Area Problems A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road? None of these 3 m 2.91 m 5.82 m None of these 3 m 2.91 m 5.82 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the park = (60 x 40) m2 = 2400 m2. Area of the lawn = 2109 m2. ∴ Area of the crossroads = (2400 - 2109) m2 = 291 m2. Let the width of the road be x metres. Then, 60x + 40x - x2 = 291 ⟹ x2 - 100x + 291 = 0 ⟹ (x - 97)(x - 3) = 0 ⟹ x = 3
Area Problems If the sides of a squares is increased by 25%, then the area of the squares will be increased by 56.25% 50% 53.75% 125% 56.25% 50% 53.75% 125% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%
Area Problems If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals. 6% 4% 9% 5% 6% 4% 9% 5% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,Percentage increase in diagonals = 5%
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