Waste Water Engineering The ratio of maximum sewage flow to average sewage flow for trunk mains having diameters more than 1.25 m, is 4 1.5 2 3 4 1.5 2 3 ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering 3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 day-incubation at 20°C, the D.O. concentration was 5 mg/l. The BOD of raw sewerage is 400 mg/l 200 mg/l 300 mg/l 100 mg/l 400 mg/l 200 mg/l 300 mg/l 100 mg/l ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering Pick up the incorrect size of stone ware sewers 67.5 cm 82.5 cm 52.5 cm None of these 67.5 cm 82.5 cm 52.5 cm None of these ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The normal value of over flow rates for plain primary sedimentation tanks, ranges between 50,000 to 60,000 litres/sqm/day 80,000 to 100,000 litres/sqm/day 40,000 to 50,000 litres/sqm/day 25,000 to 35,000 litres/sqm/day 50,000 to 60,000 litres/sqm/day 80,000 to 100,000 litres/sqm/day 40,000 to 50,000 litres/sqm/day 25,000 to 35,000 litres/sqm/day ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering 1000 kg of sewage contains 0.225 kg in solution Both A and C of above 0.112 kg in suspension 0.112 kg in solution 0.225 kg in solution Both A and C of above 0.112 kg in suspension 0.112 kg in solution ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The settling velocity of a spherical particle of diameter less than 0.1 mm as per Stock’s law, is Vs = 218 (Gs – Gw)d² [(3T + 70)/100] Vs = 218 (Gs – Gw)d [(3T + 70)/100] Vs = 418 (Gs – Gw) d [(3T + 70)/100] Vs = 418 (Gs – Gw)d² [(3T + 70)/100] Vs = 218 (Gs – Gw)d² [(3T + 70)/100] Vs = 218 (Gs – Gw)d [(3T + 70)/100] Vs = 418 (Gs – Gw) d [(3T + 70)/100] Vs = 418 (Gs – Gw)d² [(3T + 70)/100] ANSWER DOWNLOAD EXAMIANS APP
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