Area Problems The radius of a circular field is 25 m. Find the area of the field. 125 ? sq m 135 ? sq m 25 ? sq m 625 ? sq m 125 ? sq m 135 ? sq m 25 ? sq m 625 ? sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = ?r2 = ? x 25 x 25 = 625? sq m.
Area Problems If the circumference of a circle is the 352 meters, then its area in m square is? 9856 8956 6589 5986 9856 8956 6589 5986 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP circumference = 2?r = 2 x (22 / 7) x r = 352? r = (352 x 7) / (22 x 2) =56 cmNow area = ?r2 = (22 / 7) x 56 x 56 m2= 9856 m2
Area Problems One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is? 4?5 m2 12 m2 15 m2 20 m 2 4?5 m2 12 m2 15 m2 20 m 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other side = ?5 2 - 42 = ? 9=3 mSo The area of the rectangular field = 4 x 3 = 12 m2
Area Problems A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road? None of these 5.82 m 3 m 2.91 m None of these 5.82 m 3 m 2.91 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the park = (60 x 40) m2 = 2400 m2. Area of the lawn = 2109 m2. ∴ Area of the crossroads = (2400 - 2109) m2 = 291 m2. Let the width of the road be x metres. Then, 60x + 40x - x2 = 291 ⟹ x2 - 100x + 291 = 0 ⟹ (x - 97)(x - 3) = 0 ⟹ x = 3
Area Problems A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be 5544 8844 7744 4444 5544 8844 7744 4444 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP length of wire = 2 ?r = 2 x (22/7 ) x 56 = 352 cmside of the square = 352/4 = 88cmarea of the square = 88 x 88 = 7744sq cm
Area Problems The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is? 29.46 km/hr. 32.72 km/hr. 36.25 km/hr. 31.68 km/hr. 29.46 km/hr. 32.72 km/hr. 36.25 km/hr. 31.68 km/hr. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference = 2?r = 2 x (22 / 7) x 70 cm = 440 cm Distance travelled in 10 revolutions = 440 x 10 cm = 4400 cm = 44 m? Speed = distance / time= 44 / 5 m/sec= (44 / 5) x (18 / 5) km/hr = 31.68 km/hr
EXAMIANS