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Area Problems

Area Problems
The radius of a circular field is 25 m. Find the area of the field.

125 ? sq m
135 ? sq m
25 ? sq m
625 ? sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = ?r2 = ? x 25 x 25 = 625? sq m.

Area Problems
Area of a square with side x is equal to the area of a triangle with base x. The altitude of the triangle is?

2x
x/2
4x
x

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let h be the altitude of triangle.So area of triangle = (1/2)xh area of square = x2From question area of square = area of triangle x2 = (1/2)xh ? h = (2x2)/x = 2x

Area Problems
If 88 m wire is required to fence a circular plot of land, then the area of the plot is?

616 m2
526 m2
556 m2
None of these

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference of circular plot= 88 m? 2 x (22/7) x r = 88? r = 88 x (7/22) x (1/2) = 14 m Now area = ?r2=( 22/7) x 14 x 14 m2= 616 m2

Area Problems
A park of 10 meters long and 8 meters broad. What is the length of the longest pole that can be placed in the park?

12.8 metres
18 metres
13.4 metres
10 metres

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length of the longest pole = ? [(10)2 + (8)2] m = ? 164 m = 12.8 m

Area Problems
The ratio of length and breadth of a rectangle is 5 : 3 .If length is 8 m more than breadth, find the area of the rectangle.

240 sq m
250 sq m
185 sq m
300 sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length of rectangle = 5kand breadth of rectangle = 3kAccording to the quecation,5k - 3k = 8 ? 2k =8? k = 4? Lenght = 5k = 5 x 4 = 20 mBreadth = 3k = 3 x 4 = 12 m? Required area = Lenght x Breadth = 20 x 12 = 240 sq m

Area Problems
The area of circle inscribed in an equilateral triangle is 462 cm . The perimeter of the triangle is?

72.6 cms
42 ? 3 cms
168 cms
126 cms

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? 22/7 x r2 = 462? r2 = (462 x 7) /22 = 147? r = 7?3 cm ? Height of the triangle = 3r = 21?3 cmNow, ? a2 = a2/4 + (3r)2? 3a2/4 = (21?3)2? a2 = (1323 x 4)/3? a = 21x 2 = 42 cm? Perimeter = 3a = 3 x 42=126 cm

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