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Area Problems

Area Problems
The radius of a circular field is 25 m. Find the area of the field.

25 ? sq m
625 ? sq m
135 ? sq m
125 ? sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = ?r2 = ? x 25 x 25 = 625? sq m.

Area Problems
What is the diameter of the circle having 3 cm radius?

12 cm
6 cm
1.5 cm
8 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Radius = Diameter/2 ? Diameter = 2 x Radius = 2 x 3 = 6 cm

Area Problems
Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 154 sq m.

8 m
12 m
7 m
13 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length of to the rope = Radius of circle According to the question,?r2 = 154 ? r2 = 154 x (7/22) = 7 x 7 = 49 ? r = ?49 = 7 m

Area Problems
If D,E and F are respectively the midpoint of the sides BC , CA and AB of a ? ABC and the area of ? ABC = 36m 2. Then area of ? DEF is?

18 cm2
12 cm 2
9 cm 2
19 cm2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of a triangle formed by joining the mid point of the sides of the triangle is 1/4th of area of the original triangle .So area of ? DEF = 36/ 4 = 9 m2

Area Problems
A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

Rs. 568
Rs. 458
Rs. 558
Rs. 456

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area to be plastered = [2(l + b) x h] + (l x b) = {[2(25 + 12) x 6] + (25 x 12)} m2 = (444 + 300) m2 = 744 m2. ∴ Cost of plastering = Rs. ❨ 744 x 75 ❩ = Rs. 558

Area Problems
One side of a parallelogram is 8.06 cm and its perpendicular distance from opposite side is 2.08 cm. What is the approximate area of the parallelogram?

14.56 cm2
12.56 cm2
22.56 cm2
16.76 cm2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of parallelogram = Base x Height = 8.06 x 2.08 = 16.76 cm2

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