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Area Problems

Area Problems
The radius of a circular field is 25 m. Find the area of the field.

125 ? sq m
135 ? sq m
25 ? sq m
625 ? sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = ?r2 = ? x 25 x 25 = 625? sq m.

Area Problems
A circular wire of radius 42 cm is cut and bent in the form of a rectangle whose sides are in the ratio of 6: 5 . The smaller side of the rectangle is?

132 cm
30 cm
60 cm
72 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Perimeter of rectangle = Circumference of circle = 2?r=2 x ( 22/7 ) x 42= 264 cm Now perimeter of rectangle = 2 x ( 6a + 5a )? 2 x (6a + 5a) = 264? a = 12Smaller side of rectangle = 5a = 60 cm

Area Problems
A rectangle has 15 cm as its length and 150 cm 2 as its area .Its area is increased to 1 1 / 3 times the original area by increasing only its length . Its new perimeter is?

80 cm
70 cm
50 cm
60 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Breadth of the rectangle = (150/15) cm= 10 cmNew area = (4/3 x 150) cm2= 200 cm2New length = 200/10 cm=20 cmNew perimeters = 2(20 + 10) cm= 60 cm

Area Problems
The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is?

36 cm
24 cm
20 cm
30 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the sides of trapezium be 5k and 3k, respectively According to the question, (1/2) x [(5k + 3k) x 12] = 384? 8k = (384 x 2)/12 = 64 ? k = 64/8 = 8 cmLength of smaller of the parallel sides = 8 x 3 = 24 cm

Area Problems
Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

56m
14m
76m
16m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.
Let the length of the rope be r mts  then,
r2 = 9856
r2 = (9856 × 7) / 22 = 3136
r = 56 m

Area Problems
The altitude of an equilateral triangle of side 2 ? 3 cm is?

? 3/2 cm
? 3/4
3 cm
1/2 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? 1/2 x 2 ? x h = ?3/4 x (2 ?3)2? h = 3 cm.

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