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Area Problems

Area Problems
The radius of a circular field is 25 m. Find the area of the field.

135 ? sq m
125 ? sq m
25 ? sq m
625 ? sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = ?r2 = ? x 25 x 25 = 625? sq m.

Area Problems
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

Data inadequate
120
40
None of these

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m

Area Problems
A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

rs.258
rs.58
rs.358
rs.158

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x  (75/100) = Rs. 258

Area Problems
If the radius of a circle is decreased by 50% , find the percentage decrease in its area.

75%
35%
65%
25%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

let original radius = r and  new radius = (50/100) r = r/2   original area =  ?r 2  and new area =  ? r / 2 2   decrease in area =  3 ?r 2 / 4 * 1 ?r 2  *100 = 75%

Area Problems
The length of minute hand of a wall clock is 7 cms. The area swept by minute hand in 30 minutes is?

147 sq. cm
210 sq. cm
77 sq. cm
154 sq. cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Angle swept in 30 min= 180° Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2 = 77 cm2

Area Problems
The ratio of the corresponding sides of two similar triangles is 3 : 4, The ratio of their areas is?

? 3: 2
4 : 3
9 : 16
3 : 4

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of similar triangle = Ratio of the square of corresponding sides = (3x)2 / (4x)2 = 9x2 / 16x2 = 9/16 = 9 : 16

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