Area Problems
The sides of a triangle area in the ratio of 1/3 : 1/4 : 1/5 and its perimeter is 94 cm. Find the length of the smallest side of the triangle .
Given ratio = 1/3 : 1/4 : 1/5 = 20 : 15 : 12Let length of the sides be 20k, 15k and 12k.Then, according to the question,20k + 15k + 12k = 94? 47k = 94? k = 94/47 = 2Smallest side = 12k = 12 x 2 = 24 cm
The man takes 3600 s for 14.4 km The man will take 88 s for 14.4 x (88/3600) = 352/1000 km = 352 m Now, circumference of circular field = 352 m ? 2?r = 352 m2 x (22/7) x r = 352 ? r = 56 m Therefore, area of the field = ?r2= (22/7) x 56 x 56 = 8 x 22 x 56 m2= 9856 sq m.
Let the longer side = l, shorter side = b and diagonal = dThen, area of rectangular carpet = l x b = 60 ....(1) And from question d + l = 5b? d = 5b - l ...(2)? d2 = 25b2 + l2 - 10 x lb? l2+ b2 = 25b2 + l2 - 10 x lb? l2+b2 = 25b2 + l2 - 10 x 60? 24b2 = 600? b = ?25 = 5 m? l = 60 / b = 60 / 5 = 12 m
EXAMIANS