Area Problems The diagonals of two squares are in the ratio of 3 : 2. Find the ratio of their areas. 9 : 4 9 : 2 9 : 5 9 : 7 9 : 4 9 : 2 9 : 5 9 : 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the diagonals of the squares be 3x and 2x.? Ratio of their areas = [(1/2) (3x2)] / [(1/2) (2x2)] = 9/4
Area Problems The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is? 260 m 280 m 360 m none of these 260 m 280 m 360 m none of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m
Area Problems The length of each side of an equilateral triangle having an area of 4?3 cm 2 is? 4 cm ?3/4 cm 3 cm 4/?3 cm 4 cm ?3/4 cm 3 cm 4/?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm
Area Problems The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres? 120 40 None of these Data inadequate 120 40 None of these Data inadequate ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m
Area Problems The diameter of a circle is 105 cm less than the circumference. What is the diameter of the circle? 48 cm 49 cm 44 cm 46 cm 48 cm 49 cm 44 cm 46 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? ?d-d = 105 cm ? (? -1 ) d = 105 cm? [(22/7)-1] x d = 105 cm? d = (7/15) x 105 cm = 49 cm
Area Problems The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field? 40 m 20 m 30 m 50 m 40 m 20 m 30 m 50 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x meters. Then, Length = 115x / 100 meters Given that, X × (115X / 100) = 460 => X = 20
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