Area Problems Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm? 154 sq.com 164 sq.com 186 sq.com 121 sq.com 154 sq.com 164 sq.com 186 sq.com 121 sq.com ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides) = 1/2 x (12 + 10) x 14 = 22 x 14/2 = 22 x 7 = 154 sq. cm
Area Problems In a rhombus, whose area is 144 sq.cmone of its diagonal is twice as long as the other, The lengths of its diagonals are? 24 cm, 48 cm 6 ?2 cm, 12?2 cm 6 cm, 12 cm 12 cm, 24 cm 24 cm, 48 cm 6 ?2 cm, 12?2 cm 6 cm, 12 cm 12 cm, 24 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of rhombus = (d1 x d2) / 2? (d x 2d ) / 2 = 144? d2 = 144? d = 12 ? Length of diagonal = 12 cm, 24 cm
Area Problems Area of a square with side x is equal to the area of a triangle with base x. The altitude of the triangle is? 4x 2x x x/2 4x 2x x x/2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let h be the altitude of triangle.So area of triangle = (1/2)xh area of square = x2From question area of square = area of triangle x2 = (1/2)xh ? h = (2x2)/x = 2x
Area Problems The diagonals of two squares are in the ratio of 3 : 2. Find the ratio of their areas. 9 : 2 9 : 7 9 : 5 9 : 4 9 : 2 9 : 7 9 : 5 9 : 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the diagonals of the squares be 3x and 2x.? Ratio of their areas = [(1/2) (3x2)] / [(1/2) (2x2)] = 9/4
Area Problems The length of each side of an equilateral triangle having an area of 4?3 cm 2 is? ?3/4 cm 4/?3 cm 3 cm 4 cm ?3/4 cm 4/?3 cm 3 cm 4 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm
Area Problems A rectangle has 20 cm as its length and 200 sq cm as its area. If the area is increased by 1 1/ 5 time the original area by increase its length only then the perimeter of the rectangle so formed (in cm) is 68 72 60 64 68 72 60 64 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP l1 = 20 cm, A1 = 200 sq cm? b1 = 200/20 = 10 cmNow, A2 = 200 x 6/5 = 240 sq cm b2 = 10 cm? l2 = 240/10 = 24 cm? Perimeter of new rectangle = 2(l2 + b2)= 2(24 + 10) = 2 x 34 = 68 cm
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