Area Problems Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm? 186 sq.com 121 sq.com 154 sq.com 164 sq.com 186 sq.com 121 sq.com 154 sq.com 164 sq.com ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides) = 1/2 x (12 + 10) x 14 = 22 x 14/2 = 22 x 7 = 154 sq. cm
Area Problems The area of a rectangular field is 15 time the sum of its length and breadth. If the length of that field is 40 m, what is the breadth of that field? 25 m 32 m 28 m 24 m 25 m 32 m 28 m 24 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length ot rectangle = 40 mLet breadth of = kThen, according of the question, (40 + k)15 = 40k ? 600 + 15k = 40k ? 25k = 600? k = 24 m
Area Problems The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field? 50 m 20 m 40 m 30 m 50 m 20 m 40 m 30 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x meters. Then, Length = 115x / 100 meters Given that, X × (115X / 100) = 460 => X = 20
Area Problems if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is? 13 cm 14cm None of these 12 cm 13 cm 14cm None of these 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let each side = x cmThen, (x + 4 )2 - x2 = 60? x 2 + 8x + 16 - x2 = 60? x = 5.5 cm
Area Problems The difference between the circumference and the radius of a circle is 37 cm. The area of a circle is? 154 sq. cm 259 sq. cm 148 sq. cm 111 sq. cm 154 sq. cm 259 sq. cm 148 sq. cm 111 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 2?r - r = 37? [(2 x 22/7) -1]r= 37? 37r / 7= 37? r = 7 So, area of the circle =(22/7) x 7 x 7 cm2= 154 cm2
Area Problems A rectangle has 20 cm as its length and 200 sq cm as its area. If the area is increased by 1 1/ 5 time the original area by increase its length only then the perimeter of the rectangle so formed (in cm) is 64 68 72 60 64 68 72 60 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP l1 = 20 cm, A1 = 200 sq cm? b1 = 200/20 = 10 cmNow, A2 = 200 x 6/5 = 240 sq cm b2 = 10 cm? l2 = 240/10 = 24 cm? Perimeter of new rectangle = 2(l2 + b2)= 2(24 + 10) = 2 x 34 = 68 cm
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