Area Problems Area of a four walls a room is 168 Sq. meters . The breadth and height of a room are 8 meters and 6 meters respectively . The length of the room is? 3.5 meters 6 meters 12 meters 14 meters 3.5 meters 6 meters 12 meters 14 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of a four walls = 2(l + 8) x 6 = 168m2? (l + 8) = 14? l = 14-8= 6 meters
Area Problems A rectangle has 15 cm as its length and 150 cm 2 as its area .Its area is increased to 1 1 / 3 times the original area by increasing only its length . Its new perimeter is? 70 cm 60 cm 80 cm 50 cm 70 cm 60 cm 80 cm 50 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Breadth of the rectangle = (150/15) cm= 10 cmNew area = (4/3 x 150) cm2= 200 cm2New length = 200/10 cm=20 cmNew perimeters = 2(20 + 10) cm= 60 cm
Area Problems One side of a parallelogram is 14 cm. Its distance from the opposite side is 16 cm. The area of the parallelogram is? 56? sq. cm 224 sq. cm 210 sq. cm 112 sq. cm 56? sq. cm 224 sq. cm 210 sq. cm 112 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of parallelogram = Side of parallelogram x distance from the opposite side= 14 x 16 cm2= 224 cm2
Area Problems A triangle with three equal sides has its area equal to 3?3 sq cm . Find its perimeter . 7?3 cm 2?3 cm 5?3 cm 6?3 cm 7?3 cm 2?3 cm 5?3 cm 6?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,?3a2/4 = 3?3 [ side = a, and area = ?3a2/4] ? a2/4 = 3 ? a2 = 3 x 4 ? a = 2?3? Required perimeter = 3a =3 x 2?3 = 6?3 cm
Area Problems The area of circle inscribed in an equilateral triangle is 462 cm . The perimeter of the triangle is? 126 cms 72.6 cms 42 ? 3 cms 168 cms 126 cms 72.6 cms 42 ? 3 cms 168 cms ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 22/7 x r2 = 462? r2 = (462 x 7) /22 = 147? r = 7?3 cm ? Height of the triangle = 3r = 21?3 cmNow, ? a2 = a2/4 + (3r)2? 3a2/4 = (21?3)2? a2 = (1323 x 4)/3? a = 21x 2 = 42 cm? Perimeter = 3a = 3 x 42=126 cm
Area Problems A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is Rs. 458 Rs. 558 Rs. 358 Rs. 258 Rs. 458 Rs. 558 Rs. 358 Rs. 258 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area to be plastered = 2 l + b × h + l × b = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m Cost of plastering = 744 × 75 100 = R s . 558
EXAMIANS