Hydraulics and Fluid Mechanics in ME The pressure intensity in kN/m2 (or kPa) at any point in a liquid is (where w = Specific weight of liquid, and h = Depth of liquid from the surface) wh w/h w h/w wh w/h w h/w ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME If velocity is zero over l/3rd of a cross-section and is uniform over remaining 2/3rd of the cross-section, then the correction factor for kinetic energy is 27/8 44078 43892 43924 27/8 44078 43892 43924 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The specific speed from 160 to 500 r.p.m. of a centrifugal pump indicates that the pump is High speed with axial flow at outlet Slow speed with radial flow at outlet High speed with radial flow at outlet Medium speed with radial flow at outlet High speed with axial flow at outlet Slow speed with radial flow at outlet High speed with radial flow at outlet Medium speed with radial flow at outlet ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A channel is said to be of most economical cross-section, if It has minimum wetted perimeter All of these It gives maximum discharge for a given cross-sectional area and bed slope It involves lesser excavation for the designed amount of discharge It has minimum wetted perimeter All of these It gives maximum discharge for a given cross-sectional area and bed slope It involves lesser excavation for the designed amount of discharge ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME An opening in the side of a tank or vessel such that the liquid surface with the tank is below the top edge of the opening, is called None of these Orifice Weir Notch None of these Orifice Weir Notch ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions) (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 ANSWER DOWNLOAD EXAMIANS APP
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