Hydraulics and Fluid Mechanics in ME The pressure intensity in kN/m2 (or kPa) at any point in a liquid is (where w = Specific weight of liquid, and h = Depth of liquid from the surface) w h/w wh w/h w h/w wh w/h ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Barometer is used to measure Atmospheric pressure Very low pressure Pressure in pipes, channels etc. Difference of pressure between two points Atmospheric pressure Very low pressure Pressure in pipes, channels etc. Difference of pressure between two points ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The center of pressure of a surface subjected to fluid pressure is the point on the surface at which resultant pres-sure acts similar to metacentre at which all hydraulic forces meet on the surface at which gravitational force acis on the surface at which resultant pres-sure acts similar to metacentre at which all hydraulic forces meet on the surface at which gravitational force acis ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The unit of surface tension is N-m N/m2 N/m N/m3 N-m N/m2 N/m N/m3 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The type of centrifugal pump preferred for a specific speed of 20 r.p.m. is High speed pump with radial flow at outlet Medium speed pump with radial flow at outlet Slow speed pump with radial flow at outlet High speed pump with axial flow at outlet High speed pump with radial flow at outlet Medium speed pump with radial flow at outlet Slow speed pump with radial flow at outlet High speed pump with axial flow at outlet ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H15/2 - Ha5/2] ANSWER DOWNLOAD EXAMIANS APP
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