Hydraulics and Fluid Mechanics in ME According to equation of continuity, a1v1 = a2v2 w1v1 = w2v2 a1/v1 = a2/v2 w1a1 = w2a2 a1v1 = a2v2 w1v1 = w2v2 a1/v1 = a2/v2 w1a1 = w2a2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The flow in which each liquid particle has a definite path and their paths do not cross each other is called uniform flow one dimensional flow turbulent flow streamline flow uniform flow one dimensional flow turbulent flow streamline flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The flow in a pipe is turbulent when Reynold number is Between 2000 and 2800 More than 2800 Less than 2000 None of these Between 2000 and 2800 More than 2800 Less than 2000 None of these ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The loss of head due to viscosity for laminar flow in pipes is (where d = Diameter of pipe, l = Length of pipe, v = Velocity of the liquid in the pipe, μ = Viscosity of the liquid, and w = Specific weight of the flowing liquid) 32μvl/wd² 4μvl/wd² 16μvl/wd² 8μvl/wd² 32μvl/wd² 4μvl/wd² 16μvl/wd² 8μvl/wd² ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In open channels, the specific energy is the Total energy per unit discharge Kinetic energy plotted above the free surface of water Total energy measured above the horizontal datum Total energy measured with respect to the datum passing through the bottom of the channel Total energy per unit discharge Kinetic energy plotted above the free surface of water Total energy measured above the horizontal datum Total energy measured with respect to the datum passing through the bottom of the channel ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions) (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2g) × H5/2 ANSWER DOWNLOAD EXAMIANS APP
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