Hydraulics and Fluid Mechanics in ME According to equation of continuity, a1/v1 = a2/v2 w1v1 = w2v2 w1a1 = w2a2 a1v1 = a2v2 a1/v1 = a2/v2 w1v1 = w2v2 w1a1 = w2a2 a1v1 = a2v2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME When the coefficient of discharge (Cd) is 0.623, then the general equation for discharge over a rectangular weir is 1.84(L - 0.1nH)H3/2 1.84(L - nH)H2 1.84(L - 0.1nH)H5/2 1.84(L - nH)H3 1.84(L - 0.1nH)H3/2 1.84(L - nH)H2 1.84(L - 0.1nH)H5/2 1.84(L - nH)H3 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In a footstep bearing, if the speed of the shaft is doubled, then the torque required to overcome the viscous resistance will be Sixteen times Eight times Double Four times Sixteen times Eight times Double Four times ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The celerity (velocity) of a pressure wave in a fluid is given by (where K = Bulk modulus, and ρ = Density of the fluid) K.ρ None of the listed here K/ρ ρ/K K.ρ None of the listed here K/ρ ρ/K ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions) (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Stoke is the unit of Dynamic viscosity in S. I. units Kinematic viscosity in C. G. S. units Dynamic viscosity in M. K. S. units Kinematic viscosity in M. K. S. units Dynamic viscosity in S. I. units Kinematic viscosity in C. G. S. units Dynamic viscosity in M. K. S. units Kinematic viscosity in M. K. S. units ANSWER DOWNLOAD EXAMIANS APP
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