Theory of Machine The number of centers in a crank driven slider crank mechanism is 6 2 4 6 2 4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A machine mounted on a single coil spring has a period of free vibration of tp . If the spring is cut into four equal parts and placed in parallel and the machine is mounted on them, then the period of free vibration of the new system will become 4 tp 16 tp tp /4 tp /16 4 tp 16 tp tp /4 tp /16 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a cam drive with uniform velocity follower, the sharp corners of the displacement diagram are rounded off at the beginning and at the end of each stroke. This is done Because of loose contact of follower with cam surface Because the uniform velocity motion is a partial parabolic motion In order to have acceleration in beginning and retardation at the end of stroke within the finite limits Because of difficulty in manufacturing cam profile Because of loose contact of follower with cam surface Because the uniform velocity motion is a partial parabolic motion In order to have acceleration in beginning and retardation at the end of stroke within the finite limits Because of difficulty in manufacturing cam profile ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The unbalanced force due to revolving masses Constant in magnitude and direction both Varies in direction but constant in magnitude Varies in magnitude and direction both Varies in magnitude but constant in direction Constant in magnitude and direction both Varies in direction but constant in magnitude Varies in magnitude and direction both Varies in magnitude but constant in direction ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The mechanism in which two are turning pairs and two are sliding pairs, is called a Double slider crank chain Elliptical trammel All of these Scotch yoke mechanism Double slider crank chain Elliptical trammel All of these Scotch yoke mechanism ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the crank is at the inner dead center, in a reciprocating steam engine, then the acceleration of the piston will be ω²r. (n - 1)/n ω²r. (n + 1)/n ω²r. n/(n + 1) ω²r. n/(n - 1) ω²r. (n - 1)/n ω²r. (n + 1)/n ω²r. n/(n + 1) ω²r. n/(n - 1) ANSWER DOWNLOAD EXAMIANS APP
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