SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

2A
120A
12A
4A

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SSC JE Electrical 2019 with solution SET-1
 What would the total loss of the 2kVA transformer corresponding to maximum efficiency be, provided the transformer has the iron of 150 W and full-load copper loss of 250W?

100 W
500 W
300 W
400 W

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SSC JE Electrical 2019 with solution SET-1
 In the full-wave rectifier circuit shown in the figure, the diodes that conduct when the positive half-wave of AC signal applied are

D1, D2
D4, D1
D2, D3
D3, D4

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