SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

2A
12A
4A
120A

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SSC JE Electrical 2019 with solution SET-1
 The meter constant of an energy meter will be given in:

kWh/Revolutions
Revolutions/kWh
kW/Revolutions
Revolutions/kW

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SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

dΦ − dA
dΦ ⁄ dA
dA ⁄ dΦ
Φ × A

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