SSC JE Electrical 2019 with solution SET-1
Reflected Light/Incident Light =

Waste light factor
Reflection factor
Maintenance factor
Absorption factor

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SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

120A
12A
4A
2A

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SSC JE Electrical 2019 with solution SET-1
 Let T be the net torque developed by the rotor runs at ω rad/s. What is the mechanical power developed?

Pmech = (2πωT)/60
Pmech = ωT
Pmech = (ωT)/60
Pmech = (2πωT)

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SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

800 W
1600 W
400 W
1200 W

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SSC JE Electrical 2019 with solution SET-1
 P = ρQHg is the water power equation. Head ‘H’ is measured in meter ‘g’ gravity constant is measured in meter/second square, then the measuring unit of ‘Q’, the flow rate of water is:

Square meter per second
Cubic meter per second
Meter per hour
Meter per second

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