SSC JE Electrical 2019 with solution SET-1 A 200 V d.c machine as Ra = 0.5 Ω and its full-load Ia= 20A. Determine the induced e.m.f when the machine acts as a motor 190 V 200 V 210 V 215 V 190 V 200 V 210 V 215 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given DataVoltage Va = 200 vArmature Resistance Ra = 0.5ΩArmature Current Ia = 20 AInduced EMF = Ea = ?The Induced EMF of a DC machine working as a Motor isEa = Va − IaRaEa = 200 − 20 × 0.5Ea = 190 V
SSC JE Electrical 2019 with solution SET-1 The direction of the arrow represents the direction of when the diode is forward biased P-N Junction Conventional current flow P-type material N-type material P-N Junction Conventional current flow P-type material N-type material ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The direction of the arrow represents the direction of the conventional current flow when the diode is forward biased.
SSC JE Electrical 2019 with solution SET-1 In the speed-time curve of a train, speed in and time are plotted km/s; sec km/h; sec km/s; hour km/h; hour km/s; sec km/h; sec km/s; hour km/h; hour ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 An alternator has 9 slots/pole. What is the value of the pitch factor if each coil spans 8 slot pitches Cos 30° Cos 10° Cos 45° Cos 60° Cos 30° Cos 10° Cos 45° Cos 60° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Coil Span = 8Pole Pitch = 9 slots/poleSlot angle (α) = 180° / Pole Pitch = 180°/9 = 20°Pitch Factor = cos(α/2) = cos (20/2)Pitch Factor = cos 10°
SSC JE Electrical 2019 with solution SET-1 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel 0.1 μF 1 μF 100 μF 50 μF 0.1 μF 1 μF 100 μF 50 μF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When the capacitance is connected in series the total capacitance is given byCeq = C1 + C2 + C3………CNCeq = 10nCeq =10 × 10 = 100 μF
SSC JE Electrical 2019 with solution SET-1 The annual load factor of a generation station is equal to (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per month) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per month) ⁄ (Max. possible demand × 8760) ANSWER DOWNLOAD EXAMIANS APP
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