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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 The voltmeter is shown in the circuit reads:

1.2 V
2.4 V
24 V
12 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Total resistance in the given circuit
R = (250 + 250)MΩ = 500 MΩ
Current I = V/R = 24/(500 × 103)
Now the Voltage in the voltmeter
= \dfrac{{24}}{{500 \times {{10}^3}}} \times 250 \times {10^3}
V = 12 V
 

SSC JE Electrical 2019 with solution SET-1
 In the speed-time curve of a train, speed in and time are plotted

km/h; hour
km/h; sec
km/s; hour
km/s; sec

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SSC JE Electrical 2019 with solution SET-1
 A single-phase circuit’s power factor can be measured with a/an

Energy meter alone
Combination of a voltmeter and ammeter
Combination of a voltmeter, ammeter, and wattmeter
Wattmeter alone

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SSC JE Electrical 2019 with solution SET-1
 Two coupled coils with L1 = L2 = 0.5H have a coupling coefficient of K = 0.75. The turn ratio N1 ⁄ N2 = ?

2
1
4
0.5

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The self-inductance is given as
L = μN2A/I
L ∝ N2
where
N is the number of turns of the solenoid
A is the area of each turn of the coil
l is the length of the solenoid
and μ is the permeability constant
L1/L2 = N21/N22
0.5/0.5 = N21/N22
N1/N2 = 1
 

SSC JE Electrical 2019 with solution SET-1
 The direction of the arrow represents the direction of when the diode is forward biased

P-N Junction
N-type material
P-type material
Conventional current flow

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The direction of the arrow represents the direction of the conventional current flow when the diode is forward biased.
 

SSC JE Electrical 2019 with solution SET-1
Please check out below figure.

1 Ω
5 Ω
2 Ω
10 Ω

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

From the figure it can be concluded that the voltmeter reads 5 volts as shown in the figure below. Based on the voltmeter and ammeter readings in the measuring network, determine the value of the resistor R Here Current I = 1/2 A = 0.5 A Voltage V = 5 V R = V/I = 0.5/5 R = 10Ω


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