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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 The voltmeter is shown in the circuit reads:

12 V
2.4 V
24 V
1.2 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Total resistance in the given circuit
R = (250 + 250)MΩ = 500 MΩ
Current I = V/R = 24/(500 × 103)
Now the Voltage in the voltmeter
= \dfrac{{24}}{{500 \times {{10}^3}}} \times 250 \times {10^3}
V = 12 V
 

SSC JE Electrical 2019 with solution SET-1
______ Opposes the change in circuit voltage

Inductive reactance
Capacitance
Resistance
Inductance

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 A coil is wound with 50 turns and a current 8A produces a flux of 200μWb. Calculate the inductance of the coil

0.125 mH
0.25 mH
1.25 mH
2.5 mH

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The inductance of the coil is given by the relation
L = Nφ/I
Where
N = number of turns = 50
φ = flux = 200μWb
I = current = 8 A
L = 50 × 200 ×  10−6 ⁄ 8
L = 1.25 mH

SSC JE Electrical 2019 with solution SET-1
In the circuit shown, the pressure coils of two wattmeters are connected to

Neutral Wire
Y
R
B

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In Two wattmeter method the current coils of the wattmeter are connected with any two lines, say R and Y and the potential coil of each wattmeter is joined across the same line, the third line i.e. B as shown below in the figure . In the circuit B is the common point for both the wattmeter.

SSC JE Electrical 2019 with solution SET-1
 An electric heater is connected across 230V and it draws a current of 2A. Then the resistance offered by the heater is?

290 ohm
11.5 ohm
115 ohm
29 ohm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given
Voltage V = 230 V
Current I = 2 A
Resistance R = V/I
R = 230/2 = 115 Ω
 

SSC JE Electrical 2019 with solution SET-1
 Identify the machine shown in the circuit

DC shunt motor
DC long shunt compound generator
DC short shunt compound motor
DC short shunt compound generator

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