SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
The voltmeter is shown in the circuit reads:

1.2 V

12 V

2.4 V

24 V

1.2 V

12 V

2.4 V

24 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
In the two wattmeter method, the readings of the two wattmeters are 500W, 500W respectively. The load power factor in a balanced 3-phase 3-wire circuit is:

0.5

1

0.8

0.9

0.5

1

0.8

0.9

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

400 W

1600 W

1200 W

800 W

400 W

1600 W

1200 W

800 W

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
Z1 and Z2 are connected in series to form a load. A wattmeter’s current coil is connected in series with the load, whereas its pressure coil is connected across Z2. The wattmeter reads

Power consumed by Z1

Power consumed by Z1 and Z2

Power consumed by Z2

Zero always

Power consumed by Z1

Power consumed by Z1 and Z2

Power consumed by Z2

Zero always

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
A coil is wound with 50 turns and a current 8A produces a flux of 200μWb. Calculate the inductance of the coil

0.125 mH

2.5 mH

0.25 mH

1.25 mH

0.125 mH

2.5 mH

0.25 mH

1.25 mH

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

dΦ ⁄ dA

dA ⁄ dΦ

dΦ − dA

Φ × A

dΦ ⁄ dA

dA ⁄ dΦ

dΦ − dA

Φ × A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MORE MCQ ON SSC JE Electrical 2019 with solution SET-1

↑