MGVCL Exam Paper (30-07-2021 Shift 3) The most commonly used method for the protection of three phase feeder is Reverse power protection Time graded protection None of these Differential protection Reverse power protection Time graded protection None of these Differential protection ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Differential Pilot Wire Protection is simply a differential protection scheme applied to feeders.Several differential schemes are applied for protection of line but Mess Price Voltage balance system and Translay Scheme are most popularly used.
MGVCL Exam Paper (30-07-2021 Shift 3) Choose the best option from the given alternatives which can be substituted for the given word/sentence.Code of diplomatic etiquette and precedence Wardrobe Secular Sheath Protocol Wardrobe Secular Sheath Protocol ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Transistors were used in Third Generation Computers Fourth Generation Computers First Generation Computers Second Generation Computers Third Generation Computers Fourth Generation Computers First Generation Computers Second Generation Computers ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) What is the full form of the acronym 'SWIFT', in financial institution? Society for Worldwide Interbank Financial Telecommunication Society website in Financial Terms Social Wide in Financial Transaction Social World interconnection in Financial Tech process Society for Worldwide Interbank Financial Telecommunication Society website in Financial Terms Social Wide in Financial Transaction Social World interconnection in Financial Tech process ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A three phase four pole 50 Hz induction motor has a rotor resistance of 0.02 Ω/phase and stand-still reactance of 0.5 Ω/phase. Calculate the speed at which the maximum torque is developed. 1525 rpm 1475 rpm 1440 rpm 1500 rpm 1525 rpm 1475 rpm 1440 rpm 1500 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Condition for maximum torque,Sm = R2/X2= 0.04Ns = (120*f)/P= (120*50)/4= 1500 rpmS = (Ns - Nr)/NsNr = Ns(1 - Sm)= 1500*(1 - 0.04)= 1440 rpm
MGVCL Exam Paper (30-07-2021 Shift 3) In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C? 0.73 H and 13.85 pF 0.73 mH and 13.85 pF 0.53 mH and 15.83 pF 0.53 H and 15.83 pF 0.73 H and 13.85 pF 0.73 mH and 13.85 pF 0.53 mH and 15.83 pF 0.53 H and 15.83 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Vc = I*Xc460 = 2*(1/(2*ᴨ*50*C))C = 2/(460*2*50*ᴨ)= 1.385*10⁻⁵ F= 13.85 FV_L = I*X_LL = V/(I*2*ᴨ*f)= 460/(2*ᴨ*50*2)= 0.7345 H
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