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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

4/?3 cm
3 cm
4 cm
?3/4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
The area of a circular field is 13.86 hectares . The cost of fencing it at the rate of 20 paisa per meter is?

Rs. 264
Rs. 324
Rs. 277.20
Rs. 198

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? 22/7 x r2 = 13.86 x 10000? r2 = (13.86 x 10000 x 7) / 22? r = 210 m ? Circumference = [2 x (22/7) x 210 ] m = 1320 m Cost of fencing = Rs. (1320 x 20)/100= Rs . 264

Area Problems
The two parallel sides of a trapezium are 1 meters and 2 meters respectively . The perpendicular distance between them is 6 meters. The area of the trapezium is?

6 sq. meters .
9 sq. meters .
12 sq. meters .
18 sq. meters .

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them= 1/2 (1 + 2) x 6 m2= 9 m2

Area Problems
If the radius of a circle is decreased by 50% , find the percentage decrease in its area.

35%
65%
75%
25%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

let original radius = r and  new radius = (50/100) r = r/2   original area =  ?r 2  and new area =  ? r / 2 2   decrease in area =  3 ?r 2 / 4 * 1 ?r 2  *100 = 75%

Area Problems
One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is?

4?5 m2
20 m 2
12 m2
15 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other side = ?5 2 - 42 = ? 9=3 mSo The area of the rectangular field = 4 x 3 = 12 m2

Area Problems
If the sides of a squares is increased by 25%, then the area of the squares will be increased by

50%
125%
56.25%
53.75%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%

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