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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

4/?3 cm
?3/4 cm
4 cm
3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
If the base of a rectangular is increased by 10% and the area is unchanged , then the corresponding altitude must to be decreased by?

10%
111/9 %
91/11 %
11%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let base = b and altitude = h Then, Area = b x h But New base = 110b / 100 = 11b / 10Let New altitude = HThen, Decrese = (h - 10h /11 )= h / 11? Required decrease per cent = (h/11) x (1 / h ) x 100 %= 91/11 %

Area Problems
The circumferences of two concentric are 176 m and 132 m respectively. what is the difference between their radii?

7 meter
44 meter
8 meter
5 meter

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? 2?R - 2?r = (176-132)? 2?(R-r) = 44? R-r = ( 44 x 7 )/ (2 x 22)= 7 m

Area Problems
Floor of a square room of side 10 m is to be completely covered with square tiles, each having length 50 cm. The smallest number of tiles needed is?

200
300
500
400

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of square room = (10)2 = 100 sq m= 100 x (100)2 sq cm= 100 x 100 x 100 sq cmNow, area of tiles = (50)2 = 50 x 50 sq cm? Number of tiles needed = (Area of square room) / (Area of tile)= (100 x 100 x 100) / (50 x 50) = 400Hence, 400 tiles will be needed.

Area Problems
A veranda 40 meters long 15 meters broad is to paved with stones each measuring 6 dm by 5 dm. the number of stones required is?

2000
3000
None of these
1000

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length = (40 x 10 ) dm = 400 dm.Breadth = (15 x 10 ) dm = 150 dm.Area of veranda = (400 x 150 ) dm2Area of one stone = (6 x 5 ) dm2? Required number of stones = (400 x 150) /(6 x 5) = 2000

Area Problems
The wheel of an engine turns 350 times round its axle to cover a distance of 1.76 km. The diameter of the wheel is

9 cm
?3 cm
3?3 cm
3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Distance covered in 1 round = (Total Distance) / (Total round)= (1.76 x 1000)/350= 176/35 m ? 2?r = (1.76 x 100) / 35 cm2? = Diameter = 17600 x 7/22 x 35 = 160 cm

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