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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

4/?3 cm
3 cm
?3/4 cm
4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
The breadth of a rectangle is 25 m. The total cost of putting a grass bed on this field was ? 12375, at the rate of ? 15 per sq m. What is the length of the rectangular field?

27 m
30 m
32 m
33 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area to the rectangular field = 12375/15 = 825 sq mAccording to the question, (L x B) = 825 [L = length and B = breadth]? L x 25 = 825 ? L = 825/25 = 33 m

Area Problems
How many circular plates of diameter d be taken out of a square plate of side 2d with minimum loss of material?

8
6
5
2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of square plate = (Side)2 = (2d)2= 4d2Area of circular plate = ? (d/2)2= ?d2/4? Number of square plates = [(4d2)/4] / [(?d2)/4]= (4 x 4)/? ? 5Since, nearest integer value is 5.

Area Problems
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

30
33
24
20

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the side of the square(ABCD) be x metres. Then, AB + BC = 2x metres. AC = √2x = (1.41x) m. Saving on 2x metres = (0.59x) m. Saving % = ❨ 0.59x x 100 ❩% = 30%

Area Problems
In a circle of radius 21 cm an arc subtends an angle of 72° at the centre. The length of the arc is?

21.6 cm
13.2 cm
19.8 cm
26.4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Arc length = 2?r (?° / 360°) = 2 x (22/7) x 21 x (72° / 360°) cm= 26.4 cm

Area Problems
If each side of a square is increased by 25%, find the percentage change in its area.

56.25%
12.25%
36.25%
16.25%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let each side of the square be a. Then, area = . a 2 New side = 125 a 100 = 5 a 4 . New area =  5 a 4 2  =  25 a 2 16   Increase in area =  25 a 2 16 - a 2 = 9 a 2 16 Increase% =  9 a 2 16 * 1 a 2 * 100  % = 56.25%.

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