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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

3 cm
4 cm
?3/4 cm
4/?3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
The breadth of a rectangle is 25 m. The total cost of putting a grass bed on this field was ? 12375, at the rate of ? 15 per sq m. What is the length of the rectangular field?

30 m
27 m
33 m
32 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area to the rectangular field = 12375/15 = 825 sq mAccording to the question, (L x B) = 825 [L = length and B = breadth]? L x 25 = 825 ? L = 825/25 = 33 m

Area Problems
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

33
30
24
20

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the side of the square(ABCD) be x metres. Then, AB + BC = 2x metres. AC = √2x = (1.41x) m. Saving on 2x metres = (0.59x) m. Saving % = ❨ 0.59x x 100 ❩% = 30%

Area Problems
The inner circumference of a circular race track, 14 m wide is 440 m . Then the radius of the outer circle is?

77 m
56 m
84 m
70 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference of a circular = 2?r? 2 x (22 / 7) x r = 440? r = [440 x (7/22) x (1/2)] = 70 m? Radius of outer circle = (70 + 14) m = 84 m

Area Problems
The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is?

none of these
260 m
280 m
360 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m

Area Problems
The perimeter of two square is 12 cm and 24 cm. The area of the bigger square is how many times that of the smaller?

5 times
4 times
2 times
3 times

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of area of 2 squares = (ratio of perimeter of 2 squares)2= (24/12)2= 4

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