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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

4 cm
3 cm
4/?3 cm
?3/4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
A man runs round a circular field of radius 50m at the speed of 12 km/hr. What is the time taken by the man to take twenty rounds of the field?

110/7 min
90/7 min
220/7 min
230/7 min

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

speed = 12 km/h =  12 × 5 18 = 10 3 m / s     distance covered =  20 × 2 × 22 7 × 50 = 44000 7 m     time taken  = distance /speed =   44000 7 × 3 10 s e c = 4400 × 3 7 × 1 60 m i n = 220 7 m i n

Area Problems
The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is?

15 meters
4 meters
None of these
3 meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m

Area Problems
A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

Rs. 258
Rs. 458
Rs. 358
Rs. 558

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area to be plastered =  2 l + b × h + l × b   = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m   Cost of plastering =  744 × 75 100 = R s . 558

Area Problems
If 88 m wire is required to fence a circular plot of land, then the area of the plot is?

None of these
616 m2
556 m2
526 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference of circular plot= 88 m? 2 x (22/7) x r = 88? r = 88 x (7/22) x (1/2) = 14 m Now area = ?r2=( 22/7) x 14 x 14 m2= 616 m2

Area Problems
The area of a trapezium is 384 sq.cm. If its parallel sides in ratio 3 : 5 and the perpendicular distance between them be 12 cm. The smaller of parallel sides is?

16 cm
40 cm
32 cm
24 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the parallel sides be 3a and 5a.So Area of trapezium = 1/2 x sum of parallel side x perpendicular distance between them.? 1/2 (3a +5a) x 12 = 384? 8a = 64? a =8? Smaller side = 3x = 3 x 8 = 24 cm.

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