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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

3 cm
?3/4 cm
4/?3 cm
4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
The sides of a triangle area in the ratio of 1/3 : 1/4 : 1/5 and its perimeter is 94 cm. Find the length of the smallest side of the triangle .

22.5 cm
27 cm
24 cm
18 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given ratio = 1/3 : 1/4 : 1/5 = 20 : 15 : 12Let length of the sides be 20k, 15k and 12k.Then, according to the question,20k + 15k + 12k = 94? 47k = 94? k = 94/47 = 2Smallest side = 12k = 12 x 2 = 24 cm

Area Problems
The ratio of the area of two square, one having and double its diagonal than the other is?

4:1
2:1
3:1
3:2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the diagonal of one square be (2d) cmThen, diagonal of another square = d cm? Area of first square = [ 1/2 x (2d)2] cm2Area of second square = (1/2 x d2) cm2? Ratio of area = (2d)2/ d2= 4/1 = 4: 1

Area Problems
The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is?

32.72 km/hr.
29.46 km/hr.
36.25 km/hr.
31.68 km/hr.

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circumference = 2?r = 2 x (22 / 7) x 70 cm = 440 cm Distance travelled in 10 revolutions = 440 x 10 cm = 4400 cm = 44 m? Speed = distance / time= 44 / 5 m/sec= (44 / 5) x (18 / 5) km/hr = 31.68 km/hr

Area Problems
The length of a rectangular field is 100 m and its breadth is 40 m. What will be the area of the field?

(4 x 102) sq m
(4 x 10) sq m
(4 x 103) sq m
(4 x 104) sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = Length x Breadth= 100 x 40 = 4000 sq m= 4 x 103 sq m

Area Problems
A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is

136
336
436
236

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

let ABCD be the given parallelogram  area of parallelogram ABCD = 2 x (area of triangle ABC)  now a = 30m, b = 14m and c = 40m  s=1/2 x (30+14+40) = 42    Area of triangle ABC =  s s - a s - b s - c      = 42 12 28 2 = 168sq m  area of parallelogram ABCD = 2 x 168 = 336 sq m

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