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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

3 cm
4 cm
?3/4 cm
4/?3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
The length of a rectangular field is increased by 60 % . By what percent would the width have to be decreased to maintain the same area?

75%
371/2%
60%
120%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length = L and breadth = BLet , New breadth = ZThen, New length = ( 160 / 100) L.= 8L / 5? 8L / 5 x Z = LBor Z = 5B/8Decrease in breadth = (B-5B/8)= 3B/8? Decrease in percent = (3B/8 x1/B ) x 100 %= 371/2%

Area Problems
The length of a rectangular field is 100 m and its breadth is 40 m. What will be the area of the field?

(4 x 103) sq m
(4 x 10) sq m
(4 x 102) sq m
(4 x 104) sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = Length x Breadth= 100 x 40 = 4000 sq m= 4 x 103 sq m

Area Problems
A railing of 288 m is required for fencing a semi-circular park. Find the area of the park. (? = 22/7)

4928 m2
8956 m2
9856 m2
9865 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the radius of the park be r, then?r + 2r = 288(? + 2)r = 288? [(22/7) + 2]r = 288? r = (288 x 7)/36 = 56 ? Area of the park = (1/2)?r2= (1/2) x (22/7) x 56 x 56= 4928

Area Problems
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

None of these
Data inadequate
40
120

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m

Area Problems
If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

120
110
130
140

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

let length = x and breadth = y then 2(x+y) = 46 => x+y = 23 x²+y² = 17² = 289 now (x+y)² = 23² => x²+y²+2xy= 529 => 289+ 2xy = 529 => xy = 120 area = xy = 120 sq.cm

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