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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

?3/4 cm
3 cm
4/?3 cm
4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm.

22
84
64
44

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let a = 13, b = 14 and c = 15. Then,  s = 1 2 a + b + c =21  (s- a) = 8, (s - b) = 7 and (s - c) = 6. Area = s s - a s - b s - c  = 21 × 8 × 7 × 6  = 84 sq.cm

Area Problems
The area of a rectangular field is 15 time the sum of its length and breadth. If the length of that field is 40 m, what is the breadth of that field?

28 m
32 m
25 m
24 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length ot rectangle = 40 mLet breadth of = kThen, according of the question, (40 + k)15 = 40k ? 600 + 15k = 40k ? 25k = 600? k = 24 m

Area Problems
The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is

378
49
1078
154

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The diameter is equal to the shortest side of the rectangle. So radius= 14/2 = 7cm. Therefore, area of circle = (r)2 = (22/7) x 49 = 154 cm2

Area Problems
The diagonals of a squares is 4?2 cm. The diagonal of another square whose area is double that of the first square is

8?2 cm
8 cm
4?2 cm
6 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Diagonal of square = ?2a [a = side]4?2 = ?2 a a = 4 cmNow, area of square = a2 = (42) = 16Side of a square whose area is 2 x 16.a12 = 32 ? a1 = ?32 ?a14?2Now, diagonal of new square = ?2a = ?2x 4 ?2 = 8 cm

Area Problems
The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.

Rs.15500
Rs.17500
Rs.16500
Rs.18500

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = 5.5 × 3.75 sq. metre. Cost for 1 sq. metre. = Rs. 800 Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500

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