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Area Problems

Area Problems
The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?

4 cm
?3/4 cm
3 cm
4/?3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm

Area Problems
The ratio between the lenght and the breadth of a rectangle is 2 : 1. If breadth is 5 cm less than the length, what will be the parimeter of the rectangle?

30 cm
40 cm
35 cm
25 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length = 2x and breadth = xAccording to the question, 2x - x = 5 ? x = 5? Required perimeter = 2(2x + x) = 6x= 30 cm

Area Problems
If the base of a rectangular is increased by 10% and the area is unchanged , then the corresponding altitude must to be decreased by?

10%
91/11 %
111/9 %
11%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let base = b and altitude = h Then, Area = b x h But New base = 110b / 100 = 11b / 10Let New altitude = HThen, Decrese = (h - 10h /11 )= h / 11? Required decrease per cent = (h/11) x (1 / h ) x 100 %= 91/11 %

Area Problems
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

2480 m2
1520 m2
2520 m2
2420 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103. Solving the two equations, we get: l = 63 and b = 40. ∴ Area = (l x b) = (63 x 40) m2 = 2520 m2

Area Problems
What is the diameter of the circle having 3 cm radius?

8 cm
6 cm
1.5 cm
12 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Radius = Diameter/2 ? Diameter = 2 x Radius = 2 x 3 = 6 cm

Area Problems
The cost of cultivating a square field at the rate of Rs. 160 per hectare is Rs. 1440. the cost of putting a fence around it at 75 paisa per meter is?

Rs. 900
Rs. 360
Rs. 1800
Rs. 810

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = 1440 / 160 hectares = 9 hectares = 90000 m2? One side = ?90000 m = 300 mSo perimeter = 4 x 300 m = 1200 m ? Cost of fencing = Rs (1200 x 75) / 100= Rs. 900

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