Area Problems The length of each side of an equilateral triangle having an area of 4?3 cm 2 is? 3 cm ?3/4 cm 4 cm 4/?3 cm 3 cm ?3/4 cm 4 cm 4/?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm
Area Problems The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres? Data inadequate 120 None of these 40 Data inadequate 120 None of these 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m
Area Problems The radius of a circular field is 25 m. Find the area of the field. 25 ? sq m 135 ? sq m 125 ? sq m 625 ? sq m 25 ? sq m 135 ? sq m 125 ? sq m 625 ? sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = ?r2 = ? x 25 x 25 = 625? sq m.
Area Problems The area of a right angled triangle is 10 sq cm. If its perpendicular is equal to 20 cm, find its base. 4 cm 1 cm 3 cm 2 cm 4 cm 1 cm 3 cm 2 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, area = 10 sq cm, perpendicular = 20 cm and base = ? area = (base x Perpendicular) / 2 ? 10 = (base x 20) / 2 ? base = 1 cm
Area Problems A room 5.44 m x 3.75 m is to be paved with square tiles. the least number of tiles required to cover the floor is? 184 192 162 176 184 192 162 176 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the room =(544 x 374) cm2size of largest square tile = H.C.F. of 544 & 374 = 34 cm Area of 1 tile = (34 x 34) cm2? Least number of tiles required = (544 x 374) / (34 x 34) = 176
Area Problems The altitude of an equilateral triangle of side 2 ? 3 cm is? 3 cm 1/2 cm ? 3/2 cm ? 3/4 3 cm 1/2 cm ? 3/2 cm ? 3/4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 1/2 x 2 ? x h = ?3/4 x (2 ?3)2? h = 3 cm.
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