Applied Mechanics and Graphic Statics The length of a Second's pendulum, is 99.0 cm 99.4 cm 101 cm 100 cm 99.0 cm 99.4 cm 101 cm 100 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics At a given instant ship ‘A’ is travelling at 6 km/h due east and ship ‘B’ is travelling at 8 km/h due north. The velocity of ‘B’ relative to ‘A’ is 10 km/hrs 1 km/hrs 2 km/hrs 7 km/hrs 10 km/hrs 1 km/hrs 2 km/hrs 7 km/hrs ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The time period of a simple pendulum depends on(i) Mass of suspended particle(ii) Length of the pendulum(iii) Acceleration due to gravity All are correct Both (i) and (iii) Only (i) Both (ii) and (iii) All are correct Both (i) and (iii) Only (i) Both (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/sec hits an identical stationary ball ‘B’ on the table. If the impact is perfectly plastic, the velocity of the ball ‘B’ just after impact would be 10 m/sec 5 m/sec Zero None of these 10 m/sec 5 m/sec Zero None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For a given velocity of a projectile, the range is maximum when the angle of projection is 0° 45° 90° 30° 0° 45° 90° 30° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
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