Applied Mechanics and Graphic Statics The length of a Second's pendulum, is 101 cm 99.4 cm 99.0 cm 100 cm 101 cm 99.4 cm 99.0 cm 100 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The characteristic of a couple is: A couple can be never the balanced by a single force Algebraic sum of moments of forces, constituting a couple, about any point, is same Algebraic sum of forces, constituting a couple is zero All listed here A couple can be never the balanced by a single force Algebraic sum of moments of forces, constituting a couple, about any point, is same Algebraic sum of forces, constituting a couple is zero All listed here ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rigid body is in a stable equilibrium if the application of any force Neither raises nor lowers the CG of the body None of above Tends to lower the CG of the body Can raise the CG of the body but cannot lower it Neither raises nor lowers the CG of the body None of above Tends to lower the CG of the body Can raise the CG of the body but cannot lower it ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A car goes round a curve of radius 100 m at 25 m/sec. The angle to the horizontal at which the road must be banked to prevent sideways friction on the car wheels is tan"1 x, where x is (Assume g = 10 m/sec²) 43898 44079 43832 43959 43898 44079 43832 43959 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/2) × [(2b + a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
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