Applied Mechanics and Graphic Statics If two forces are in equilibrium, then the forces must (i) Be equal in magnitude (ii) Be opposite in sense (iii) Act along the same line All (i), (ii) and (iii) Only (i) (i) and (ii) (i) and (iii) All (i), (ii) and (iii) Only (i) (i) and (ii) (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The necessary condition of equilibrium of a body is: Algebraic sum of the moments of the forces about a point must be zero Algebraic sum of vertical components of all the forces must be zero Algebraic sum of horizontal components of all the forces must be zero All (A), (B) and (C) Algebraic sum of the moments of the forces about a point must be zero Algebraic sum of vertical components of all the forces must be zero Algebraic sum of horizontal components of all the forces must be zero All (A), (B) and (C) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Joule is equivalent to 9.81 Newton metre 1 Newton metre 1 dyne metre 1 kg wt metre 9.81 Newton metre 1 Newton metre 1 dyne metre 1 kg wt metre ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two forces act an angle of 120°. If the greater force is 50 kg and their resultant is perpendicular to the smaller force, the smaller force is 25 kg 30 kg 50 kg 40 kg 25 kg 30 kg 50 kg 40 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The ratio of the moment of inertia of a rectangle about its centroidal axis to the moment of inertia about its base, is 43832 43834 43894 2 43832 43834 43894 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In case of S.H.M. the period of oscillation (T), is given by T = 2ω/π² T = 2π/ω T = π/2ω T = 2/ω T = 2ω/π² T = 2π/ω T = π/2ω T = 2/ω ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS