Applied Mechanics and Graphic Statics One Newton is equivalent to 1 kg. wt 1/9.81 kg. wt 981 dyne 9.81 kg. wt 1 kg. wt 1/9.81 kg. wt 981 dyne 9.81 kg. wt ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The reaction between the sphere and the wall of the arrangement made is 102.5 kg 108.5 kg 110 kg 105.5 kg 102.5 kg 108.5 kg 110 kg 105.5 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The beam shown in below figure is supported by a hinge at ‘A’ and a roller at ‘B’. The reaction RA of the hinged support ‘A’ of the beam, is 10.8 t 10.6 t 10.2 t 10.4 t 10.8 t 10.6 t 10.2 t 10.4 t ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A block in the shape of a parallelepiped of sides 1m × 2m × 3m lies on the surface. Which of the faces gives maximum stable block? Equally stable on all faces 2 m × 3 m 1 m × 3 m 1 m × 2 m Equally stable on all faces 2 m × 3 m 1 m × 3 m 1 m × 2 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A weight ‘W’ is suspended at the free end of a light member hinged to a vertical wall. If the angle of inclination of the member with the upper wall is θ°, the force introduced in the member, is W cosec θ W sin θ W cos θ W sec θ W cosec θ W sin θ W cos θ W sec θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
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