Applied Mechanics and Graphic Statics Engineer's units of force, is Dyne in absolute units Newton and dyne in absolute units All listed here Newton in absolute units Dyne in absolute units Newton and dyne in absolute units All listed here Newton in absolute units ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rod 5 m in length is moving in a vertical plane. When it is inclined at 60° to horizontal, its lower end is moving horizontally at 3 m/sec and upper end is moving in vertical direction. The velocity of its upper end, is 0.5 m/sec 1.0 m/sec 2.5 m/sec 1.5 m/sec 0.5 m/sec 1.0 m/sec 2.5 m/sec 1.5 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of an elastic string of natural length ‘l’ and modulus ‘X’ is kept fixed while to the other end is attached a particle of mass m which is hanging freely under gravity. The particle is pulled down vertically through a distance ‘x’, held at rest and then released.The motion is A damped oscillatory motion None of these A rectilinear motion with constant speed A simple harmonic motion A damped oscillatory motion None of these A rectilinear motion with constant speed A simple harmonic motion ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body of weight ‘w’ placed on an inclined plane is acted upon by a force ‘P’ parallel to the plane which causes the body just to move up the plane. If the angle of inclination of the plane is ‘θ’ and angle of friction is ‘φ’, the minimum value of ‘P’, is w sinθ cos(θ - φ)/sin φ w cos (θ + φ)/cos φ w sin (φ - θ)/cos φ w sin (θ - φ)/cos φ w sinθ cos(θ - φ)/sin φ w cos (θ + φ)/cos φ w sin (φ - θ)/cos φ w sin (θ - φ)/cos φ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The reaction between the sphere and the wall of the arrangement made is 110 kg 105.5 kg 108.5 kg 102.5 kg 110 kg 105.5 kg 108.5 kg 102.5 kg ANSWER DOWNLOAD EXAMIANS APP
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