Area Problems The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre. Rs.17500 Rs.15500 Rs.16500 Rs.18500 Rs.17500 Rs.15500 Rs.16500 Rs.18500 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 5.5 × 3.75 sq. metre. Cost for 1 sq. metre. = Rs. 800 Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500
Area Problems The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side. 9 cm 3 cm ?3 cm 3?3 cm 9 cm 3 cm ?3 cm 3?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm
Area Problems Area of a square is 1/2 hectare. The diagonal of the square is? 250 meter 100 meter 50 meter 50? 2 meter 250 meter 100 meter 50 meter 50? 2 meter ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1/2 hectare = 10000 / 2 m2= 5000 m2Again Area = 1/2 x (Diagonal)2So 1/2 x (Diagonal)2 = 5000m2? Diagonal2= 10000 ? Diagonal = 100
Area Problems Four horses are be tethered at four concern of a square plot of side 63 meters, so that they just cannot reach one another. The area left ungrazed is? 785.8 m2 675.5 m2 780.6 m2 850.5 m2 785.8 m2 675.5 m2 780.6 m2 850.5 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area left ungrazed = [(63 x 63) - (4 x 1/4 x 22/7 x (63/2)2] m2= (63 x 63 - (99 x 63)/2 ) m2= 63 x (63 - 99/2) m2= 850.5 m2
Area Problems A triangle with three equal sides has its area equal to 3?3 sq cm . Find its perimeter . 6?3 cm 7?3 cm 2?3 cm 5?3 cm 6?3 cm 7?3 cm 2?3 cm 5?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,?3a2/4 = 3?3 [ side = a, and area = ?3a2/4] ? a2/4 = 3 ? a2 = 3 x 4 ? a = 2?3? Required perimeter = 3a =3 x 2?3 = 6?3 cm
Area Problems A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road? 2.91 m 3 m None of these 5.82 m 2.91 m 3 m None of these 5.82 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the park = (60 x 40) m2 = 2400 m2. Area of the lawn = 2109 m2. ∴ Area of the crossroads = (2400 - 2109) m2 = 291 m2. Let the width of the road be x metres. Then, 60x + 40x - x2 = 291 ⟹ x2 - 100x + 291 = 0 ⟹ (x - 97)(x - 3) = 0 ⟹ x = 3
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