Engineering Mechanics The law of the machine is (where P = Effort applied to lift the load, m = A constant which is equal to the slope of the line, W = Load lifted, and C = Another constant which represents the machine friction.) P = mW + C P = C - mW P = mW - C P = m/W + C P = mW + C P = C - mW P = mW - C P = m/W + C ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of percussion of the homogeneous rod of length ‘L’ suspended at the top will be L/2 L/3 3L/4 2L/3 L/2 L/3 3L/4 2L/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The range of projectile (R) on an upward inclined plane is 2u². sin (α + β). cos α/g. cos² β g. cos² β/2u². sin (α - β). cos α 2u². sin (α - β). cos α/g. cos² β g. cos² β/2u². sin (α + β). cos α 2u². sin (α + β). cos α/g. cos² β g. cos² β/2u². sin (α - β). cos α 2u². sin (α - β). cos α/g. cos² β g. cos² β/2u². sin (α + β). cos α ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is h²/(kG² + h²) h/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h h²/(kG² + h²) h/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act Perpendicular to the wall at its upper end Zero at its upper end Downward at its upper end Upward at its upper end Perpendicular to the wall at its upper end Zero at its upper end Downward at its upper end Upward at its upper end ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The C.G. of a solid hemisphere lies on the central radius 3r At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base ANSWER DOWNLOAD EXAMIANS APP
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