Stoichiometry The heat of adsorption of a gas caused by Van der Walls forces of attraction and capillarity is equal to the heat of Wetting Normal condensation Difference of A and B Sum of A and B Wetting Normal condensation Difference of A and B Sum of A and B ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Heat of neutralisation of a strong acid and strong base is always a constant value, i.e., 57 KJ/Kg mole. This is because Only OH⁻ and H⁺ ions react in every case The strong base and strong acid reacts completely The salt formed does not hydrolyse The strong base and strong acid reacts in aqueous solution Only OH⁻ and H⁺ ions react in every case The strong base and strong acid reacts completely The salt formed does not hydrolyse The strong base and strong acid reacts in aqueous solution ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry pH value of an alkaline solution is Constant over a wide range 7 > 7 < 7 Constant over a wide range 7 > 7 < 7 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry With rise in pressure, the solubility of gases in solvent, at a fixed temperature Decreases Decreases linearly Remains unchanged Increases Decreases Decreases linearly Remains unchanged Increases ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry The heat evolved in the combustion of benzene is represented by the equation: C₆H₆ + 7.5 O₂ = 6CO₂ + 3H₂O, ΔH = 3264.6 kJ/kg. mole The heat energy change, when 39 gm of C₆H₆ is burnt in an open container, will be __________ kJ/kgmole. -2448.45 +1632.3 -1632.3 +816.15 -2448.45 +1632.3 -1632.3 +816.15 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Pick out the wrong unit conversion. None of these 1 mm Hg = 1 torr = 133.3 Pa 1 atm. = 760 mm Hg = 29.92 inch Hg = 14.7 psi = 1.013 bar = 1.013 kgf/cm² 1 kPa = 100 bar None of these 1 mm Hg = 1 torr = 133.3 Pa 1 atm. = 760 mm Hg = 29.92 inch Hg = 14.7 psi = 1.013 bar = 1.013 kgf/cm² 1 kPa = 100 bar ANSWER DOWNLOAD EXAMIANS APP
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