One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH₄ + 2O₂ → CO₂ + 2H₂O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. Mole fraction of water vapour in the product gases is about

Stoichiometry
One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH₄ + 2O₂ → CO₂ + 2H₂O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. Mole fraction of water vapour in the product gases is about

0.67

0.33

0.40

0.19

0.67

0.33

0.40

0.19

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Stoichiometry
N.T.P. corresponds to

1 atm.absolute pressure& 0°C

101.325 KPa gauge pressure & 0°C

760 torr & 15°C

760 mm Hg gauge pressure & 0°C

1 atm.absolute pressure& 0°C

101.325 KPa gauge pressure & 0°C

760 torr & 15°C

760 mm Hg gauge pressure & 0°C

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Stoichiometry
At room temperature, the product [H⁺] [OH⁻] in a solution is 10⁻¹⁴ moles/litre. If, [OH⁻] = 10⁻⁶ moles/litre, then the pH of the solution will be

6

10

8

12

6

10

8

12

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Stoichiometry
Specific gravity on API scale is given by the relation(where, G = specific gravity at 15.5°C).

°API = 200(G - 1)

°API = 145 - (145/G)

°API = (141.5/G) - 131.5

°API = (140/G) - 130

°API = 200(G - 1)

°API = 145 - (145/G)

°API = (141.5/G) - 131.5

°API = (140/G) - 130

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Stoichiometry
80 kg of Na₂SO₄ (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na₂SO₄ .10H₂O crystals separate out. The weight fraction of Na₂SO₄ in the remaining solution is

0.18

0.24

1

0.18

0.24

1

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Stoichiometry
For a given mass of a gas at constant temperature, if the volume 'V' becomes three times, then the pressure 'P' will become

9P²

9P

3P

P/3

9P²

9P

3P

P/3

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Stoichiometry

Stoichiometry N.T.P. corresponds to

Stoichiometry At room temperature, the product [H⁺] [OH⁻] in a solution is 10⁻¹⁴ moles/litre. If, [OH⁻] = 10⁻⁶ moles/litre, then the pH of the solution will be

Stoichiometry Specific gravity on API scale is given by the relation(where, G = specific gravity at 15.5°C).

Stoichiometry 80 kg of Na₂SO₄ (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na₂SO₄ .10H₂O crystals separate out. The weight fraction of Na₂SO₄ in the remaining solution is

Stoichiometry For a given mass of a gas at constant temperature, if the volume 'V' becomes three times, then the pressure 'P' will become

Stoichiometry
N.T.P. corresponds to

Stoichiometry
At room temperature, the product [H⁺] [OH⁻] in a solution is 10⁻¹⁴ moles/litre. If, [OH⁻] = 10⁻⁶ moles/litre, then the pH of the solution will be

Stoichiometry
Specific gravity on API scale is given by the relation(where, G = specific gravity at 15.5°C).

Stoichiometry
80 kg of Na₂SO₄ (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na₂SO₄ .10H₂O crystals separate out. The weight fraction of Na₂SO₄ in the remaining solution is

Stoichiometry
For a given mass of a gas at constant temperature, if the volume 'V' becomes three times, then the pressure 'P' will become